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Solution - Absolute value equations

Exact form: x=3,1
x=3 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|3x1|=|2x+10|
without the absolute value bars:

|x|=|y|2|3x1|=|2x+10|
x=+y2(3x1)=(2x+10)
x=y2(3x1)=(2x+10)
+x=y2(3x1)=(2x+10)
x=y2((3x1))=(2x+10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|3x1|=|2x+10|
x=+y , +x=y2(3x1)=(2x+10)
x=y , x=y2(3x1)=(2x+10)

2. Solve the two equations for x

14 additional steps

2·(3x-1)=(2x+10)

Expand the parentheses:

2·3x+2·-1=(2x+10)

Multiply the coefficients:

6x+2·-1=(2x+10)

Simplify the arithmetic:

6x-2=(2x+10)

Subtract from both sides:

(6x-2)-2x=(2x+10)-2x

Group like terms:

(6x-2x)-2=(2x+10)-2x

Simplify the arithmetic:

4x-2=(2x+10)-2x

Group like terms:

4x-2=(2x-2x)+10

Simplify the arithmetic:

4x2=10

Add to both sides:

(4x-2)+2=10+2

Simplify the arithmetic:

4x=10+2

Simplify the arithmetic:

4x=12

Divide both sides by :

(4x)4=124

Simplify the fraction:

x=124

Find the greatest common factor of the numerator and denominator:

x=(3·4)(1·4)

Factor out and cancel the greatest common factor:

x=3

14 additional steps

2·(3x-1)=-(2x+10)

Expand the parentheses:

2·3x+2·-1=-(2x+10)

Multiply the coefficients:

6x+2·-1=-(2x+10)

Simplify the arithmetic:

6x-2=-(2x+10)

Expand the parentheses:

6x2=2x10

Add to both sides:

(6x-2)+2x=(-2x-10)+2x

Group like terms:

(6x+2x)-2=(-2x-10)+2x

Simplify the arithmetic:

8x-2=(-2x-10)+2x

Group like terms:

8x-2=(-2x+2x)-10

Simplify the arithmetic:

8x2=10

Add to both sides:

(8x-2)+2=-10+2

Simplify the arithmetic:

8x=10+2

Simplify the arithmetic:

8x=8

Divide both sides by :

(8x)8=-88

Simplify the fraction:

x=-88

Simplify the fraction:

x=1

3. List the solutions

x=3,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|3x1|
y=|2x+10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.