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Solution - Absolute value equations

Exact form: x=98
x=\frac{9}{8}
Mixed number form: x=118
x=1\frac{1}{8}
Decimal form: x=1.125
x=1.125

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|2x3|=|4x3|
without the absolute value bars:

|x|=|y|2|2x3|=|4x3|
x=+y2(2x3)=(4x3)
x=y2(2x3)=(4x3)
+x=y2(2x3)=(4x3)
x=y2((2x3))=(4x3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|2x3|=|4x3|
x=+y , +x=y2(2x3)=(4x3)
x=y , x=y2(2x3)=(4x3)

2. Solve the two equations for x

8 additional steps

2·(2x-3)=(4x-3)

Expand the parentheses:

2·2x+2·-3=(4x-3)

Multiply the coefficients:

4x+2·-3=(4x-3)

Simplify the arithmetic:

4x-6=(4x-3)

Subtract from both sides:

(4x-6)-4x=(4x-3)-4x

Group like terms:

(4x-4x)-6=(4x-3)-4x

Simplify the arithmetic:

-6=(4x-3)-4x

Group like terms:

-6=(4x-4x)-3

Simplify the arithmetic:

6=3

The statement is false:

6=3

The equation is false so it has no solution.

13 additional steps

2·(2x-3)=-(4x-3)

Expand the parentheses:

2·2x+2·-3=-(4x-3)

Multiply the coefficients:

4x+2·-3=-(4x-3)

Simplify the arithmetic:

4x-6=-(4x-3)

Expand the parentheses:

4x6=4x+3

Add to both sides:

(4x-6)+4x=(-4x+3)+4x

Group like terms:

(4x+4x)-6=(-4x+3)+4x

Simplify the arithmetic:

8x-6=(-4x+3)+4x

Group like terms:

8x-6=(-4x+4x)+3

Simplify the arithmetic:

8x6=3

Add to both sides:

(8x-6)+6=3+6

Simplify the arithmetic:

8x=3+6

Simplify the arithmetic:

8x=9

Divide both sides by :

(8x)8=98

Simplify the fraction:

x=98

3. Graph

Each line represents the function of one side of the equation:
y=2|2x3|
y=|4x3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.