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Solution - Absolute value equations

Exact form: x=-4,87
x=-4 , \frac{8}{7}
Mixed number form: x=-4,117
x=-4 , 1\frac{1}{7}
Decimal form: x=4,1.143
x=-4 , 1.143

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
2|2x1|=3|x2|
without the absolute value bars:

|x|=|y|2|2x1|=3|x2|
x=+y2(2x1)=3(x2)
x=y2(2x1)=3((x2))
+x=y2(2x1)=3(x2)
x=y2((2x1))=3(x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|2|2x1|=3|x2|
x=+y , +x=y2(2x1)=3(x2)
x=y , x=y2(2x1)=3((x2))

2. Solve the two equations for x

12 additional steps

2·(2x-1)=3·(x-2)

Expand the parentheses:

2·2x+2·-1=3·(x-2)

Multiply the coefficients:

4x+2·-1=3·(x-2)

Simplify the arithmetic:

4x-2=3·(x-2)

Expand the parentheses:

4x-2=3x+3·-2

Simplify the arithmetic:

4x2=3x6

Subtract from both sides:

(4x-2)-3x=(3x-6)-3x

Group like terms:

(4x-3x)-2=(3x-6)-3x

Simplify the arithmetic:

x-2=(3x-6)-3x

Group like terms:

x-2=(3x-3x)-6

Simplify the arithmetic:

x2=6

Add to both sides:

(x-2)+2=-6+2

Simplify the arithmetic:

x=6+2

Simplify the arithmetic:

x=4

17 additional steps

2·(2x-1)=3·(-(x-2))

Expand the parentheses:

2·2x+2·-1=3·(-(x-2))

Multiply the coefficients:

4x+2·-1=3·(-(x-2))

Simplify the arithmetic:

4x-2=3·(-(x-2))

Expand the parentheses:

4x-2=3·(-x+2)

4x-2=3·-x+3·2

Group like terms:

4x-2=(3·-1)x+3·2

Multiply the coefficients:

4x-2=-3x+3·2

Simplify the arithmetic:

4x2=3x+6

Add to both sides:

(4x-2)+3x=(-3x+6)+3x

Group like terms:

(4x+3x)-2=(-3x+6)+3x

Simplify the arithmetic:

7x-2=(-3x+6)+3x

Group like terms:

7x-2=(-3x+3x)+6

Simplify the arithmetic:

7x2=6

Add to both sides:

(7x-2)+2=6+2

Simplify the arithmetic:

7x=6+2

Simplify the arithmetic:

7x=8

Divide both sides by :

(7x)7=87

Simplify the fraction:

x=87

3. List the solutions

x=-4,87
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=2|2x1|
y=3|x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.