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Solution - Absolute value equations

Exact form: x=53,-15
x=\frac{5}{3} , -\frac{1}{5}
Mixed number form: x=123,-15
x=1\frac{2}{3} , -\frac{1}{5}
Decimal form: x=1.667,0.2
x=1.667 , -0.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
12|x+3|=|2x-1|
without the absolute value bars:

|x|=|y|12|x+3|=|2x-1|
x=+y12(x+3)=(2x-1)
x=-y12(x+3)=-(2x-1)
+x=y12(x+3)=(2x-1)
-x=y12(-(x+3))=(2x-1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|12|x+3|=|2x-1|
x=+y , +x=y12(x+3)=(2x-1)
x=-y , -x=y12(x+3)=-(2x-1)

2. Solve the two equations for x

26 additional steps

12·(x+3)=(2x-1)

Multiply the fraction(s):

(1·(x+3))2=(2x-1)

Break up the fraction:

x2+32=(2x-1)

Subtract from both sides:

(x2+32)-2x=(2x-1)-2x

Group like terms:

(x2-2x)+32=(2x-1)-2x

Group the coefficients:

(12-2)x+32=(2x-1)-2x

Convert the integer into a fraction:

(12+-42)x+32=(2x-1)-2x

Combine the fractions:

(1-4)2x+32=(2x-1)-2x

Combine the numerators:

-32x+32=(2x-1)-2x

Group like terms:

-32x+32=(2x-2x)-1

Simplify the arithmetic:

-32x+32=-1

Subtract from both sides:

(-32x+32)-32=-1-32

Combine the fractions:

-32x+(3-3)2=-1-32

Combine the numerators:

-32x+02=-1-32

Reduce the zero numerator:

-32x+0=-1-32

Simplify the arithmetic:

-32x=-1-32

Convert the integer into a fraction:

-32x=-22+-32

Combine the fractions:

-32x=(-2-3)2

Combine the numerators:

-32x=-52

Multiply both sides by inverse fraction :

(-32x)·2-3=(-52)·2-3

Move the negative sign from the denominator to the numerator:

-32x·-23=(-52)·2-3

Group like terms:

(-32·-23)x=(-52)·2-3

Multiply the coefficients:

(-3·-2)(2·3)x=(-52)·2-3

Simplify the arithmetic:

1x=(-52)·2-3

x=(-52)·2-3

Move the negative sign from the denominator to the numerator:

x=-52·-23

Multiply the fraction(s):

x=(-5·-2)(2·3)

Simplify the arithmetic:

x=53

24 additional steps

12·(x+3)=-(2x-1)

Multiply the fraction(s):

(1·(x+3))2=-(2x-1)

Break up the fraction:

x2+32=-(2x-1)

Expand the parentheses:

x2+32=-2x+1

Add to both sides:

(x2+32)+2x=(-2x+1)+2x

Group like terms:

(x2+2x)+32=(-2x+1)+2x

Group the coefficients:

(12+2)x+32=(-2x+1)+2x

Convert the integer into a fraction:

(12+42)x+32=(-2x+1)+2x

Combine the fractions:

(1+4)2x+32=(-2x+1)+2x

Combine the numerators:

52x+32=(-2x+1)+2x

Group like terms:

52x+32=(-2x+2x)+1

Simplify the arithmetic:

52x+32=1

Subtract from both sides:

(52x+32)-32=1-32

Combine the fractions:

52x+(3-3)2=1-32

Combine the numerators:

52x+02=1-32

Reduce the zero numerator:

52x+0=1-32

Simplify the arithmetic:

52x=1-32

Convert the integer into a fraction:

52x=22+-32

Combine the fractions:

52x=(2-3)2

Combine the numerators:

52x=-12

Multiply both sides by inverse fraction :

(52x)·25=(-12)·25

Group like terms:

(52·25)x=(-12)·25

Multiply the coefficients:

(5·2)(2·5)x=(-12)·25

Simplify the fraction:

x=(-12)·25

Multiply the fraction(s):

x=(-1·2)(2·5)

Simplify the arithmetic:

x=-15

3. List the solutions

x=53,-15
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=12|x+3|
y=|2x-1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.