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Solution - Absolute value equations

Exact form:

h = - 2, 0

h=-2 , 0

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$0.4 | 10 h - 5 | = | 6 h + 2 |$
without the absolute value bars:

$\| x \| = \| y \|$	$0.4 \| 10 h - 5 \| = \| 6 h + 2 \|$
$x = + y$	$0.4 (10 h - 5) = (6 h + 2)$
$x = - y$	$0.4 (10 h - 5) = - (6 h + 2)$
$+ x = y$	$0.4 (10 h - 5) = (6 h + 2)$
$- x = y$	$0.4 (- (10 h - 5)) = (6 h + 2)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$0.4 \| 10 h - 5 \| = \| 6 h + 2 \|$
$x = + y$ , $+ x = y$	$0.4 (10 h - 5) = (6 h + 2)$
$x = - y$ , $- x = y$	$0.4 (10 h - 5) = - (6 h + 2)$

2. Solve the two equations for h

16 additional steps

$0.4 \cdot (10 h - 5) = (6 h + 2)$

Expand the parentheses:

$0.4 \cdot 10 h + 0.4 \cdot - 5 = (6 h + 2)$

Multiply the coefficients:

$4 h + 0.4 \cdot - 5 = (6 h + 2)$

Simplify the arithmetic:

$4 h - 2 = (6 h + 2)$

Subtract from both sides:

$(4 h - 2) - 6 h = (6 h + 2) - 6 h$

Group like terms:

$(4 h - 6 h) - 2 = (6 h + 2) - 6 h$

Simplify the arithmetic:

$- 2 h - 2 = (6 h + 2) - 6 h$

Group like terms:

$- 2 h - 2 = (6 h - 6 h) + 2$

Simplify the arithmetic:

$- 2 h - 2 = 2$

Add to both sides:

$(- 2 h - 2) + 2 = 2 + 2$

Simplify the arithmetic:

$- 2 h = 2 + 2$

Simplify the arithmetic:

$- 2 h = 4$

Divide both sides by :

$\frac{(- 2 h)}{- 2} = \frac{4}{- 2}$

Cancel out the negatives:

$\frac{2 h}{2} = \frac{4}{- 2}$

Simplify the fraction:

$h = \frac{4}{- 2}$

Move the negative sign from the denominator to the numerator:

$h = \frac{- 4}{2}$

Find the greatest common factor of the numerator and denominator:

$h = \frac{(- 2 \cdot 2)}{(1 \cdot 2)}$

Factor out and cancel the greatest common factor:

$h = - 2$

12 additional steps

$0.4 \cdot (10 h - 5) = - (6 h + 2)$

Expand the parentheses:

$0.4 \cdot 10 h + 0.4 \cdot - 5 = - (6 h + 2)$

Multiply the coefficients:

$4 h + 0.4 \cdot - 5 = - (6 h + 2)$

Simplify the arithmetic:

$4 h - 2 = - (6 h + 2)$

Expand the parentheses:

$4 h - 2 = - 6 h - 2$

Add to both sides:

$(4 h - 2) + 6 h = (- 6 h - 2) + 6 h$

Group like terms:

$(4 h + 6 h) - 2 = (- 6 h - 2) + 6 h$

Simplify the arithmetic:

$10 h - 2 = (- 6 h - 2) + 6 h$

Group like terms:

$10 h - 2 = (- 6 h + 6 h) - 2$

Simplify the arithmetic:

$10 h - 2 = - 2$

Add to both sides:

$(10 h - 2) + 2 = - 2 + 2$

Simplify the arithmetic:

$10 h = - 2 + 2$

Simplify the arithmetic:

$10 h = 0$

Divide both sides by the coefficient:

$h = 0$

3. List the solutions

$h = - 2, 0$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = 0.4 | 10 h - 5 |$
$y = | 6 h + 2 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for h

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for h

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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