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Solution - Absolute value equations

Exact form: x=811,10
x=\frac{8}{11} , 10
Decimal form: x=0.727,10
x=0.727 , 10

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
3|2x3|=|5x+1|
without the absolute value bars:

|x|=|y|3|2x3|=|5x+1|
x=+y3(2x3)=(5x+1)
x=y3(2x3)=(5x+1)
+x=y3(2x3)=(5x+1)
x=y3((2x3))=(5x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y|3|2x3|=|5x+1|
x=+y , +x=y3(2x3)=(5x+1)
x=y , x=y3(2x3)=(5x+1)

2. Solve the two equations for x

14 additional steps

-3·(2x-3)=(5x+1)

Expand the parentheses:

-3·2x-3·-3=(5x+1)

Multiply the coefficients:

-6x-3·-3=(5x+1)

Simplify the arithmetic:

-6x+9=(5x+1)

Subtract from both sides:

(-6x+9)-5x=(5x+1)-5x

Group like terms:

(-6x-5x)+9=(5x+1)-5x

Simplify the arithmetic:

-11x+9=(5x+1)-5x

Group like terms:

-11x+9=(5x-5x)+1

Simplify the arithmetic:

11x+9=1

Subtract from both sides:

(-11x+9)-9=1-9

Simplify the arithmetic:

11x=19

Simplify the arithmetic:

11x=8

Divide both sides by :

(-11x)-11=-8-11

Cancel out the negatives:

11x11=-8-11

Simplify the fraction:

x=-8-11

Cancel out the negatives:

x=811

14 additional steps

-3·(2x-3)=-(5x+1)

Expand the parentheses:

-3·2x-3·-3=-(5x+1)

Multiply the coefficients:

-6x-3·-3=-(5x+1)

Simplify the arithmetic:

-6x+9=-(5x+1)

Expand the parentheses:

6x+9=5x1

Add to both sides:

(-6x+9)+5x=(-5x-1)+5x

Group like terms:

(-6x+5x)+9=(-5x-1)+5x

Simplify the arithmetic:

-x+9=(-5x-1)+5x

Group like terms:

-x+9=(-5x+5x)-1

Simplify the arithmetic:

x+9=1

Subtract from both sides:

(-x+9)-9=-1-9

Simplify the arithmetic:

x=19

Simplify the arithmetic:

x=10

Multiply both sides by :

-x·-1=-10·-1

Remove the one(s):

x=-10·-1

Simplify the arithmetic:

x=10

3. List the solutions

x=811,10
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=3|2x3|
y=|5x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.