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Solution - Absolute value equations

Exact form: x=5,1
x=-5 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+3|=|6x+8|
without the absolute value bars:

|x|=|y||5x+3|=|6x+8|
x=+y(5x+3)=(6x+8)
x=y(5x+3)=((6x+8))
+x=y(5x+3)=(6x+8)
x=y((5x+3))=(6x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+3|=|6x+8|
x=+y , +x=y(5x+3)=(6x+8)
x=y , x=y(5x+3)=((6x+8))

2. Solve the two equations for x

9 additional steps

-(5x+3)=-(6x+8)

Expand the parentheses:

-5x-3=-(6x+8)

Expand the parentheses:

5x3=6x8

Add to both sides:

(-5x-3)+6x=(-6x-8)+6x

Group like terms:

(-5x+6x)-3=(-6x-8)+6x

Simplify the arithmetic:

x-3=(-6x-8)+6x

Group like terms:

x-3=(-6x+6x)-8

Simplify the arithmetic:

x3=8

Add to both sides:

(x-3)+3=-8+3

Simplify the arithmetic:

x=8+3

Simplify the arithmetic:

x=5

14 additional steps

-(5x+3)=-(-(6x+8))

Expand the parentheses:

-5x-3=-(-(6x+8))

Resolve the double minus:

5x3=6x+8

Subtract from both sides:

(-5x-3)-6x=(6x+8)-6x

Group like terms:

(-5x-6x)-3=(6x+8)-6x

Simplify the arithmetic:

-11x-3=(6x+8)-6x

Group like terms:

-11x-3=(6x-6x)+8

Simplify the arithmetic:

11x3=8

Add to both sides:

(-11x-3)+3=8+3

Simplify the arithmetic:

11x=8+3

Simplify the arithmetic:

11x=11

Divide both sides by :

(-11x)-11=11-11

Cancel out the negatives:

11x11=11-11

Simplify the fraction:

x=11-11

Move the negative sign from the denominator to the numerator:

x=-1111

Simplify the fraction:

x=1

3. List the solutions

x=5,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+3|
y=|6x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.