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Solution - Absolute value equations

Exact form: x=-47,-23
x=-\frac{4}{7} , -\frac{2}{3}
Decimal form: x=0.571,0.667
x=-0.571 , -0.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5x+3|=|2x+1|
without the absolute value bars:

|x|=|y||5x+3|=|2x+1|
x=+y(5x+3)=(2x+1)
x=y(5x+3)=(2x+1)
+x=y(5x+3)=(2x+1)
x=y((5x+3))=(2x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5x+3|=|2x+1|
x=+y , +x=y(5x+3)=(2x+1)
x=y , x=y(5x+3)=(2x+1)

2. Solve the two equations for x

12 additional steps

-(5x+3)=(2x+1)

Expand the parentheses:

-5x-3=(2x+1)

Subtract from both sides:

(-5x-3)-2x=(2x+1)-2x

Group like terms:

(-5x-2x)-3=(2x+1)-2x

Simplify the arithmetic:

-7x-3=(2x+1)-2x

Group like terms:

-7x-3=(2x-2x)+1

Simplify the arithmetic:

7x3=1

Add to both sides:

(-7x-3)+3=1+3

Simplify the arithmetic:

7x=1+3

Simplify the arithmetic:

7x=4

Divide both sides by :

(-7x)-7=4-7

Cancel out the negatives:

7x7=4-7

Simplify the fraction:

x=4-7

Move the negative sign from the denominator to the numerator:

x=-47

13 additional steps

-(5x+3)=-(2x+1)

Expand the parentheses:

-5x-3=-(2x+1)

Expand the parentheses:

5x3=2x1

Add to both sides:

(-5x-3)+2x=(-2x-1)+2x

Group like terms:

(-5x+2x)-3=(-2x-1)+2x

Simplify the arithmetic:

-3x-3=(-2x-1)+2x

Group like terms:

-3x-3=(-2x+2x)-1

Simplify the arithmetic:

3x3=1

Add to both sides:

(-3x-3)+3=-1+3

Simplify the arithmetic:

3x=1+3

Simplify the arithmetic:

3x=2

Divide both sides by :

(-3x)-3=2-3

Cancel out the negatives:

3x3=2-3

Simplify the fraction:

x=2-3

Move the negative sign from the denominator to the numerator:

x=-23

3. List the solutions

x=-47,-23
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5x+3|
y=|2x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.