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Solution - Absolute value equations

Exact form: q=27,43
q=\frac{2}{7} , \frac{4}{3}
Mixed number form: q=27,113
q=\frac{2}{7} , 1\frac{1}{3}
Decimal form: q=0.286,1.333
q=0.286 , 1.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|5q3|=|2q+1|
without the absolute value bars:

|x|=|y||5q3|=|2q+1|
x=+y(5q3)=(2q+1)
x=y(5q3)=(2q+1)
+x=y(5q3)=(2q+1)
x=y((5q3))=(2q+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||5q3|=|2q+1|
x=+y , +x=y(5q3)=(2q+1)
x=y , x=y(5q3)=(2q+1)

2. Solve the two equations for q

12 additional steps

-(5q-3)=(2q+1)

Expand the parentheses:

-5q+3=(2q+1)

Subtract from both sides:

(-5q+3)-2q=(2q+1)-2q

Group like terms:

(-5q-2q)+3=(2q+1)-2q

Simplify the arithmetic:

-7q+3=(2q+1)-2q

Group like terms:

-7q+3=(2q-2q)+1

Simplify the arithmetic:

7q+3=1

Subtract from both sides:

(-7q+3)-3=1-3

Simplify the arithmetic:

7q=13

Simplify the arithmetic:

7q=2

Divide both sides by :

(-7q)-7=-2-7

Cancel out the negatives:

7q7=-2-7

Simplify the fraction:

q=-2-7

Cancel out the negatives:

q=27

13 additional steps

-(5q-3)=-(2q+1)

Expand the parentheses:

-5q+3=-(2q+1)

Expand the parentheses:

5q+3=2q1

Add to both sides:

(-5q+3)+2q=(-2q-1)+2q

Group like terms:

(-5q+2q)+3=(-2q-1)+2q

Simplify the arithmetic:

-3q+3=(-2q-1)+2q

Group like terms:

-3q+3=(-2q+2q)-1

Simplify the arithmetic:

3q+3=1

Subtract from both sides:

(-3q+3)-3=-1-3

Simplify the arithmetic:

3q=13

Simplify the arithmetic:

3q=4

Divide both sides by :

(-3q)-3=-4-3

Cancel out the negatives:

3q3=-4-3

Simplify the fraction:

q=-4-3

Cancel out the negatives:

q=43

3. List the solutions

q=27,43
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|5q3|
y=|2q+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.