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Solution - Absolute value equations

Exact form: x=0
x=0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|2x+5|+|2x5|=0

Add |2x5| to both sides of the equation:

|2x+5|+|2x5||2x5|=|2x5|

Simplify the arithmetic

|2x+5|=|2x5|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|2x+5|=|2x5|
without the absolute value bars:

|x|=|y||2x+5|=|2x5|
x=+y(2x+5)=(2x5)
x=y(2x+5)=(2x5)
+x=y(2x+5)=(2x5)
x=y((2x+5))=(2x5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||2x+5|=|2x5|
x=+y , +x=y(2x+5)=(2x5)
x=y , x=y(2x+5)=(2x5)

3. Solve the two equations for x

7 additional steps

-(2x+5)=-(2x-5)

Expand the parentheses:

-2x-5=-(2x-5)

Expand the parentheses:

2x5=2x+5

Add to both sides:

(-2x-5)+2x=(-2x+5)+2x

Group like terms:

(-2x+2x)-5=(-2x+5)+2x

Simplify the arithmetic:

-5=(-2x+5)+2x

Group like terms:

-5=(-2x+2x)+5

Simplify the arithmetic:

5=5

The statement is false:

5=5

The equation is false so it has no solution.

10 additional steps

-(2x+5)=-(-(2x-5))

Expand the parentheses:

-2x-5=-(-(2x-5))

Resolve the double minus:

2x5=2x5

Subtract from both sides:

(-2x-5)-2x=(2x-5)-2x

Group like terms:

(-2x-2x)-5=(2x-5)-2x

Simplify the arithmetic:

-4x-5=(2x-5)-2x

Group like terms:

-4x-5=(2x-2x)-5

Simplify the arithmetic:

4x5=5

Add to both sides:

(-4x-5)+5=-5+5

Simplify the arithmetic:

4x=5+5

Simplify the arithmetic:

4x=0

Divide both sides by the coefficient:

x=0

4. Graph

Each line represents the function of one side of the equation:
y=|2x+5|
y=|2x5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.