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Solution - Absolute value equations

Exact form: z=32
z=\frac{3}{2}
Mixed number form: z=112
z=1\frac{1}{2}
Decimal form: z=1.5
z=1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z|=|z3|
without the absolute value bars:

|x|=|y||z|=|z3|
x=+y(z)=(z3)
x=y(z)=(z3)
+x=y(z)=(z3)
x=y(z)=(z3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z|=|z3|
x=+y , +x=y(z)=(z3)
x=y , x=y(z)=(z3)

2. Solve the two equations for z

4 additional steps

z=(z-3)

Subtract from both sides:

z-z=(z-3)-z

Simplify the arithmetic:

0=(z-3)-z

Group like terms:

0=(z-z)-3

Simplify the arithmetic:

0=3

The statement is false:

0=3

The equation is false so it has no solution.

6 additional steps

z=-(z-3)

Expand the parentheses:

z=z+3

Add to both sides:

z+z=(-z+3)+z

Simplify the arithmetic:

2z=(-z+3)+z

Group like terms:

2z=(-z+z)+3

Simplify the arithmetic:

2z=3

Divide both sides by :

(2z)2=32

Simplify the fraction:

z=32

3. Graph

Each line represents the function of one side of the equation:
y=|z|
y=|z3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.