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Solution - Absolute value equations

Exact form: z=2,2
z=-2 , 2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z4|=2|z1|
without the absolute value bars:

|x|=|y||z4|=2|z1|
x=+y(z4)=2(z1)
x=y(z4)=2((z1))
+x=y(z4)=2(z1)
x=y(z4)=2(z1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z4|=2|z1|
x=+y , +x=y(z4)=2(z1)
x=y , x=y(z4)=2((z1))

2. Solve the two equations for z

12 additional steps

(z-4)=2·(z-1)

Expand the parentheses:

(z-4)=2z+2·-1

Simplify the arithmetic:

(z-4)=2z-2

Subtract from both sides:

(z-4)-2z=(2z-2)-2z

Group like terms:

(z-2z)-4=(2z-2)-2z

Simplify the arithmetic:

-z-4=(2z-2)-2z

Group like terms:

-z-4=(2z-2z)-2

Simplify the arithmetic:

z4=2

Add to both sides:

(-z-4)+4=-2+4

Simplify the arithmetic:

z=2+4

Simplify the arithmetic:

z=2

Multiply both sides by :

-z·-1=2·-1

Remove the one(s):

z=2·-1

Simplify the arithmetic:

z=2

16 additional steps

(z-4)=2·(-(z-1))

Expand the parentheses:

(z-4)=2·(-z+1)

(z-4)=2·-z+2·1

Group like terms:

(z-4)=(2·-1)z+2·1

Multiply the coefficients:

(z-4)=-2z+2·1

Simplify the arithmetic:

(z-4)=-2z+2

Add to both sides:

(z-4)+2z=(-2z+2)+2z

Group like terms:

(z+2z)-4=(-2z+2)+2z

Simplify the arithmetic:

3z-4=(-2z+2)+2z

Group like terms:

3z-4=(-2z+2z)+2

Simplify the arithmetic:

3z4=2

Add to both sides:

(3z-4)+4=2+4

Simplify the arithmetic:

3z=2+4

Simplify the arithmetic:

3z=6

Divide both sides by :

(3z)3=63

Simplify the fraction:

z=63

Find the greatest common factor of the numerator and denominator:

z=(2·3)(1·3)

Factor out and cancel the greatest common factor:

z=2

3. List the solutions

z=2,2
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|z4|
y=2|z1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.