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Solution - Absolute value equations

Exact form: z=-1,13
z=-1 , \frac{1}{3}
Decimal form: z=1,0.333
z=-1 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z1|=2|z|
without the absolute value bars:

|x|=|y||z1|=2|z|
x=+y(z1)=2(z)
x=y(z1)=2((z))
+x=y(z1)=2(z)
x=y(z1)=2(z)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z1|=2|z|
x=+y , +x=y(z1)=2(z)
x=y , x=y(z1)=2((z))

2. Solve the two equations for z

9 additional steps

(z-1)=2z

Subtract from both sides:

(z-1)-2z=(2z)-2z

Group like terms:

(z-2z)-1=(2z)-2z

Simplify the arithmetic:

-z-1=(2z)-2z

Simplify the arithmetic:

z1=0

Add to both sides:

(-z-1)+1=0+1

Simplify the arithmetic:

z=0+1

Simplify the arithmetic:

z=1

Multiply both sides by :

-z·-1=1·-1

Remove the one(s):

z=1·-1

Remove the one(s):

z=1

10 additional steps

(z-1)=2·-z

Group like terms:

(z-1)=(2·-1)z

Multiply the coefficients:

(z-1)=-2z

Add to both sides:

(z-1)+2z=(-2z)+2z

Group like terms:

(z+2z)-1=(-2z)+2z

Simplify the arithmetic:

3z-1=(-2z)+2z

Simplify the arithmetic:

3z1=0

Add to both sides:

(3z-1)+1=0+1

Simplify the arithmetic:

3z=0+1

Simplify the arithmetic:

3z=1

Divide both sides by :

(3z)3=13

Simplify the fraction:

z=13

3. List the solutions

z=-1,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|z1|
y=2|z|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.