Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: z=0
z=0

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|z1|+|z+1|=0

Add |z+1| to both sides of the equation:

|z1|+|z+1||z+1|=|z+1|

Simplify the arithmetic

|z1|=|z+1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z1|=|z+1|
without the absolute value bars:

|x|=|y||z1|=|z+1|
x=+y(z1)=(z+1)
x=y(z1)=(z+1)
+x=y(z1)=(z+1)
x=y(z1)=(z+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z1|=|z+1|
x=+y , +x=y(z1)=(z+1)
x=y , x=y(z1)=(z+1)

3. Solve the two equations for z

9 additional steps

(z-1)=-(z+1)

Expand the parentheses:

(z-1)=-z-1

Add to both sides:

(z-1)+z=(-z-1)+z

Group like terms:

(z+z)-1=(-z-1)+z

Simplify the arithmetic:

2z-1=(-z-1)+z

Group like terms:

2z-1=(-z+z)-1

Simplify the arithmetic:

2z1=1

Add to both sides:

(2z-1)+1=-1+1

Simplify the arithmetic:

2z=1+1

Simplify the arithmetic:

2z=0

Divide both sides by the coefficient:

z=0

6 additional steps

(z-1)=-(-(z+1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(z-1)=z+1

Subtract from both sides:

(z-1)-z=(z+1)-z

Group like terms:

(z-z)-1=(z+1)-z

Simplify the arithmetic:

-1=(z+1)-z

Group like terms:

-1=(z-z)+1

Simplify the arithmetic:

1=1

The statement is false:

1=1

The equation is false so it has no solution.

4. List the solutions

z=0
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|z1|
y=|z+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.