Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: z=3
z=3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z+2|=|z8|
without the absolute value bars:

|x|=|y||z+2|=|z8|
x=+y(z+2)=(z8)
x=y(z+2)=(z8)
+x=y(z+2)=(z8)
x=y(z+2)=(z8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z+2|=|z8|
x=+y , +x=y(z+2)=(z8)
x=y , x=y(z+2)=(z8)

2. Solve the two equations for z

5 additional steps

(z+2)=(z-8)

Subtract from both sides:

(z+2)-z=(z-8)-z

Group like terms:

(z-z)+2=(z-8)-z

Simplify the arithmetic:

2=(z-8)-z

Group like terms:

2=(z-z)-8

Simplify the arithmetic:

2=8

The statement is false:

2=8

The equation is false so it has no solution.

12 additional steps

(z+2)=-(z-8)

Expand the parentheses:

(z+2)=-z+8

Add to both sides:

(z+2)+z=(-z+8)+z

Group like terms:

(z+z)+2=(-z+8)+z

Simplify the arithmetic:

2z+2=(-z+8)+z

Group like terms:

2z+2=(-z+z)+8

Simplify the arithmetic:

2z+2=8

Subtract from both sides:

(2z+2)-2=8-2

Simplify the arithmetic:

2z=82

Simplify the arithmetic:

2z=6

Divide both sides by :

(2z)2=62

Simplify the fraction:

z=62

Find the greatest common factor of the numerator and denominator:

z=(3·2)(1·2)

Factor out and cancel the greatest common factor:

z=3

3. Graph

Each line represents the function of one side of the equation:
y=|z+2|
y=|z8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.