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Solution - Absolute value equations

Exact form: z=-3,-53
z=-3 , -\frac{5}{3}
Mixed number form: z=-3,-123
z=-3 , -1\frac{2}{3}
Decimal form: z=3,1.667
z=-3 , -1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|z+1|=2|z+2|
without the absolute value bars:

|x|=|y||z+1|=2|z+2|
x=+y(z+1)=2(z+2)
x=y(z+1)=2((z+2))
+x=y(z+1)=2(z+2)
x=y(z+1)=2(z+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||z+1|=2|z+2|
x=+y , +x=y(z+1)=2(z+2)
x=y , x=y(z+1)=2((z+2))

2. Solve the two equations for z

12 additional steps

(z+1)=2·(z+2)

Expand the parentheses:

(z+1)=2z+2·2

Simplify the arithmetic:

(z+1)=2z+4

Subtract from both sides:

(z+1)-2z=(2z+4)-2z

Group like terms:

(z-2z)+1=(2z+4)-2z

Simplify the arithmetic:

-z+1=(2z+4)-2z

Group like terms:

-z+1=(2z-2z)+4

Simplify the arithmetic:

z+1=4

Subtract from both sides:

(-z+1)-1=4-1

Simplify the arithmetic:

z=41

Simplify the arithmetic:

z=3

Multiply both sides by :

-z·-1=3·-1

Remove the one(s):

z=3·-1

Simplify the arithmetic:

z=3

14 additional steps

(z+1)=2·(-(z+2))

Expand the parentheses:

(z+1)=2·(-z-2)

(z+1)=2·-z+2·-2

Group like terms:

(z+1)=(2·-1)z+2·-2

Multiply the coefficients:

(z+1)=-2z+2·-2

Simplify the arithmetic:

(z+1)=-2z-4

Add to both sides:

(z+1)+2z=(-2z-4)+2z

Group like terms:

(z+2z)+1=(-2z-4)+2z

Simplify the arithmetic:

3z+1=(-2z-4)+2z

Group like terms:

3z+1=(-2z+2z)-4

Simplify the arithmetic:

3z+1=4

Subtract from both sides:

(3z+1)-1=-4-1

Simplify the arithmetic:

3z=41

Simplify the arithmetic:

3z=5

Divide both sides by :

(3z)3=-53

Simplify the fraction:

z=-53

3. List the solutions

z=-3,-53
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|z+1|
y=2|z+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.