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Solution - Absolute value equations

Exact form: y=3,1
y=-3 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|y3||2y|=0

Add |2y| to both sides of the equation:

|y3||2y|+|2y|=|2y|

Simplify the arithmetic

|y3|=|2y|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|y3|=|2y|
without the absolute value bars:

|x|=|y||y3|=|2y|
x=+y(y3)=(2y)
x=y(y3)=((2y))
+x=y(y3)=(2y)
x=y(y3)=(2y)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||y3|=|2y|
x=+y , +x=y(y3)=(2y)
x=y , x=y(y3)=((2y))

3. Solve the two equations for y

9 additional steps

(y-3)=2y

Subtract from both sides:

(y-3)-2y=(2y)-2y

Group like terms:

(y-2y)-3=(2y)-2y

Simplify the arithmetic:

-y-3=(2y)-2y

Simplify the arithmetic:

y3=0

Add to both sides:

(-y-3)+3=0+3

Simplify the arithmetic:

y=0+3

Simplify the arithmetic:

y=3

Multiply both sides by :

-y·-1=3·-1

Remove the one(s):

y=3·-1

Simplify the arithmetic:

y=3

8 additional steps

(y-3)=-2y

Add to both sides:

(y-3)+3=(-2y)+3

Simplify the arithmetic:

y=(-2y)+3

Add to both sides:

y+2y=((-2y)+3)+2y

Simplify the arithmetic:

3y=((-2y)+3)+2y

Group like terms:

3y=(-2y+2y)+3

Simplify the arithmetic:

3y=3

Divide both sides by :

(3y)3=33

Simplify the fraction:

y=33

Simplify the fraction:

y=1

4. List the solutions

y=3,1
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|y3|
y=|2y|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.