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Solution - Absolute value equations

Exact form: y=14,-52
y=\frac{1}{4} , -\frac{5}{2}
Mixed number form: y=14,-212
y=\frac{1}{4} , -2\frac{1}{2}
Decimal form: y=0.25,2.5
y=0.25 , -2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|y3|=|3y2|
without the absolute value bars:

|x|=|y||y3|=|3y2|
x=+y(y3)=(3y2)
x=y(y3)=(3y2)
+x=y(y3)=(3y2)
x=y(y3)=(3y2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||y3|=|3y2|
x=+y , +x=y(y3)=(3y2)
x=y , x=y(y3)=(3y2)

2. Solve the two equations for y

9 additional steps

(y-3)=(-3y-2)

Add to both sides:

(y-3)+3y=(-3y-2)+3y

Group like terms:

(y+3y)-3=(-3y-2)+3y

Simplify the arithmetic:

4y-3=(-3y-2)+3y

Group like terms:

4y-3=(-3y+3y)-2

Simplify the arithmetic:

4y3=2

Add to both sides:

(4y-3)+3=-2+3

Simplify the arithmetic:

4y=2+3

Simplify the arithmetic:

4y=1

Divide both sides by :

(4y)4=14

Simplify the fraction:

y=14

12 additional steps

(y-3)=-(-3y-2)

Expand the parentheses:

(y-3)=3y+2

Subtract from both sides:

(y-3)-3y=(3y+2)-3y

Group like terms:

(y-3y)-3=(3y+2)-3y

Simplify the arithmetic:

-2y-3=(3y+2)-3y

Group like terms:

-2y-3=(3y-3y)+2

Simplify the arithmetic:

2y3=2

Add to both sides:

(-2y-3)+3=2+3

Simplify the arithmetic:

2y=2+3

Simplify the arithmetic:

2y=5

Divide both sides by :

(-2y)-2=5-2

Cancel out the negatives:

2y2=5-2

Simplify the fraction:

y=5-2

Move the negative sign from the denominator to the numerator:

y=-52

3. List the solutions

y=14,-52
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|y3|
y=|3y2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.