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Solution - Absolute value equations

Exact form: y=2,4
y=-2 , 4

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|y+5|=|2y1|
without the absolute value bars:

|x|=|y||y+5|=|2y1|
x=+y(y+5)=(2y1)
x=y(y+5)=(2y1)
+x=y(y+5)=(2y1)
x=y(y+5)=(2y1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||y+5|=|2y1|
x=+y , +x=y(y+5)=(2y1)
x=y , x=y(y+5)=(2y1)

2. Solve the two equations for y

11 additional steps

(y+5)=(-2y-1)

Add to both sides:

(y+5)+2y=(-2y-1)+2y

Group like terms:

(y+2y)+5=(-2y-1)+2y

Simplify the arithmetic:

3y+5=(-2y-1)+2y

Group like terms:

3y+5=(-2y+2y)-1

Simplify the arithmetic:

3y+5=1

Subtract from both sides:

(3y+5)-5=-1-5

Simplify the arithmetic:

3y=15

Simplify the arithmetic:

3y=6

Divide both sides by :

(3y)3=-63

Simplify the fraction:

y=-63

Find the greatest common factor of the numerator and denominator:

y=(-2·3)(1·3)

Factor out and cancel the greatest common factor:

y=2

11 additional steps

(y+5)=-(-2y-1)

Expand the parentheses:

(y+5)=2y+1

Subtract from both sides:

(y+5)-2y=(2y+1)-2y

Group like terms:

(y-2y)+5=(2y+1)-2y

Simplify the arithmetic:

-y+5=(2y+1)-2y

Group like terms:

-y+5=(2y-2y)+1

Simplify the arithmetic:

y+5=1

Subtract from both sides:

(-y+5)-5=1-5

Simplify the arithmetic:

y=15

Simplify the arithmetic:

y=4

Multiply both sides by :

-y·-1=-4·-1

Remove the one(s):

y=-4·-1

Simplify the arithmetic:

y=4

3. List the solutions

y=2,4
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|y+5|
y=|2y1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.