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Solution - Absolute value equations

Exact form: x=12,6
x=12 , 6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x|=|3x24|
without the absolute value bars:

|x|=|y||x|=|3x24|
x=+y(x)=(3x24)
x=y(x)=(3x24)
+x=y(x)=(3x24)
x=y(x)=(3x24)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x|=|3x24|
x=+y , +x=y(x)=(3x24)
x=y , x=y(x)=(3x24)

2. Solve the two equations for x

9 additional steps

x=(3x-24)

Subtract from both sides:

x-3x=(3x-24)-3x

Simplify the arithmetic:

-2x=(3x-24)-3x

Group like terms:

-2x=(3x-3x)-24

Simplify the arithmetic:

2x=24

Divide both sides by :

(-2x)-2=-24-2

Cancel out the negatives:

2x2=-24-2

Simplify the fraction:

x=-24-2

Cancel out the negatives:

x=242

Find the greatest common factor of the numerator and denominator:

x=(12·2)(1·2)

Factor out and cancel the greatest common factor:

x=12

8 additional steps

x=-(3x-24)

Expand the parentheses:

x=3x+24

Add to both sides:

x+3x=(-3x+24)+3x

Simplify the arithmetic:

4x=(-3x+24)+3x

Group like terms:

4x=(-3x+3x)+24

Simplify the arithmetic:

4x=24

Divide both sides by :

(4x)4=244

Simplify the fraction:

x=244

Find the greatest common factor of the numerator and denominator:

x=(6·4)(1·4)

Factor out and cancel the greatest common factor:

x=6

3. List the solutions

x=12,6
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x|
y=|3x24|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.