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Solution - Absolute value equations

Exact form: x=38,310
x=\frac{3}{8} , \frac{3}{10}
Decimal form: x=0.375,0.3
x=0.375 , 0.3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x|=3|3x1|
without the absolute value bars:

|x|=|y||x|=3|3x1|
x=+y(x)=3(3x1)
x=y(x)=3((3x1))
+x=y(x)=3(3x1)
x=y(x)=3(3x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x|=3|3x1|
x=+y , +x=y(x)=3(3x1)
x=y , x=y(x)=3((3x1))

2. Solve the two equations for x

10 additional steps

x=3·(3x-1)

Expand the parentheses:

x=3·3x+3·-1

Multiply the coefficients:

x=9x+3·-1

Simplify the arithmetic:

x=9x3

Subtract from both sides:

x-9x=(9x-3)-9x

Simplify the arithmetic:

-8x=(9x-3)-9x

Group like terms:

-8x=(9x-9x)-3

Simplify the arithmetic:

8x=3

Divide both sides by :

(-8x)-8=-3-8

Cancel out the negatives:

8x8=-3-8

Simplify the fraction:

x=-3-8

Cancel out the negatives:

x=38

9 additional steps

x=3·(-(3x-1))

Expand the parentheses:

x=3·(-3x+1)

Expand the parentheses:

x=3·-3x+3·1

Multiply the coefficients:

x=-9x+3·1

Simplify the arithmetic:

x=9x+3

Add to both sides:

x+9x=(-9x+3)+9x

Simplify the arithmetic:

10x=(-9x+3)+9x

Group like terms:

10x=(-9x+9x)+3

Simplify the arithmetic:

10x=3

Divide both sides by :

(10x)10=310

Simplify the fraction:

x=310

3. List the solutions

x=38,310
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x|
y=3|3x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.