Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=92
x=\frac{9}{2}
Mixed number form: x=412
x=4\frac{1}{2}
Decimal form: x=4.5
x=4.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x|+|x9|=0

Add |x9| to both sides of the equation:

|x|+|x9||x9|=|x9|

Simplify the arithmetic

|x|=|x9|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x|=|x9|
without the absolute value bars:

|x|=|y||x|=|x9|
x=+y(x)=(x9)
x=y(x)=(x9)
+x=y(x)=(x9)
x=y(x)=(x9)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x|=|x9|
x=+y , +x=y(x)=(x9)
x=y , x=y(x)=(x9)

3. Solve the two equations for x

6 additional steps

x=-(x-9)

Expand the parentheses:

x=x+9

Add to both sides:

x+x=(-x+9)+x

Simplify the arithmetic:

2x=(-x+9)+x

Group like terms:

2x=(-x+x)+9

Simplify the arithmetic:

2x=9

Divide both sides by :

(2x)2=92

Simplify the fraction:

x=92

5 additional steps

x=-(-(x-9))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

x=x9

Subtract from both sides:

x-x=(x-9)-x

Simplify the arithmetic:

0=(x-9)-x

Group like terms:

0=(x-x)-9

Simplify the arithmetic:

0=9

The statement is false:

0=9

The equation is false so it has no solution.

4. List the solutions

x=92
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x|
y=|x9|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.