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Solution - Absolute value equations

Exact form: x=-83,65
x=-\frac{8}{3} , \frac{6}{5}
Mixed number form: x=-223,115
x=-2\frac{2}{3} , 1\frac{1}{5}
Decimal form: x=2.667,1.2
x=-2.667 , 1.2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x7|=|4x+1|
without the absolute value bars:

|x|=|y||x7|=|4x+1|
x=+y(x7)=(4x+1)
x=y(x7)=(4x+1)
+x=y(x7)=(4x+1)
x=y(x7)=(4x+1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x7|=|4x+1|
x=+y , +x=y(x7)=(4x+1)
x=y , x=y(x7)=(4x+1)

2. Solve the two equations for x

11 additional steps

(x-7)=(4x+1)

Subtract from both sides:

(x-7)-4x=(4x+1)-4x

Group like terms:

(x-4x)-7=(4x+1)-4x

Simplify the arithmetic:

-3x-7=(4x+1)-4x

Group like terms:

-3x-7=(4x-4x)+1

Simplify the arithmetic:

3x7=1

Add to both sides:

(-3x-7)+7=1+7

Simplify the arithmetic:

3x=1+7

Simplify the arithmetic:

3x=8

Divide both sides by :

(-3x)-3=8-3

Cancel out the negatives:

3x3=8-3

Simplify the fraction:

x=8-3

Move the negative sign from the denominator to the numerator:

x=-83

10 additional steps

(x-7)=-(4x+1)

Expand the parentheses:

(x-7)=-4x-1

Add to both sides:

(x-7)+4x=(-4x-1)+4x

Group like terms:

(x+4x)-7=(-4x-1)+4x

Simplify the arithmetic:

5x-7=(-4x-1)+4x

Group like terms:

5x-7=(-4x+4x)-1

Simplify the arithmetic:

5x7=1

Add to both sides:

(5x-7)+7=-1+7

Simplify the arithmetic:

5x=1+7

Simplify the arithmetic:

5x=6

Divide both sides by :

(5x)5=65

Simplify the fraction:

x=65

3. List the solutions

x=-83,65
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x7|
y=|4x+1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.