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Solution - Absolute value equations

Exact form: x=-152,-14
x=-\frac{15}{2} , -\frac{1}{4}
Mixed number form: x=-712,-14
x=-7\frac{1}{2} , -\frac{1}{4}
Decimal form: x=7.5,0.25
x=-7.5 , -0.25

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x7|=|3x+8|
without the absolute value bars:

|x|=|y||x7|=|3x+8|
x=+y(x7)=(3x+8)
x=y(x7)=(3x+8)
+x=y(x7)=(3x+8)
x=y(x7)=(3x+8)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x7|=|3x+8|
x=+y , +x=y(x7)=(3x+8)
x=y , x=y(x7)=(3x+8)

2. Solve the two equations for x

11 additional steps

(x-7)=(3x+8)

Subtract from both sides:

(x-7)-3x=(3x+8)-3x

Group like terms:

(x-3x)-7=(3x+8)-3x

Simplify the arithmetic:

-2x-7=(3x+8)-3x

Group like terms:

-2x-7=(3x-3x)+8

Simplify the arithmetic:

2x7=8

Add to both sides:

(-2x-7)+7=8+7

Simplify the arithmetic:

2x=8+7

Simplify the arithmetic:

2x=15

Divide both sides by :

(-2x)-2=15-2

Cancel out the negatives:

2x2=15-2

Simplify the fraction:

x=15-2

Move the negative sign from the denominator to the numerator:

x=-152

10 additional steps

(x-7)=-(3x+8)

Expand the parentheses:

(x-7)=-3x-8

Add to both sides:

(x-7)+3x=(-3x-8)+3x

Group like terms:

(x+3x)-7=(-3x-8)+3x

Simplify the arithmetic:

4x-7=(-3x-8)+3x

Group like terms:

4x-7=(-3x+3x)-8

Simplify the arithmetic:

4x7=8

Add to both sides:

(4x-7)+7=-8+7

Simplify the arithmetic:

4x=8+7

Simplify the arithmetic:

4x=1

Divide both sides by :

(4x)4=-14

Simplify the fraction:

x=-14

3. List the solutions

x=-152,-14
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x7|
y=|3x+8|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.