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Solution - Absolute value equations

Exact form: x=2
x=2

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x7|+|x+3|=0

Add |x+3| to both sides of the equation:

|x7|+|x+3||x+3|=|x+3|

Simplify the arithmetic

|x7|=|x+3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x7|=|x+3|
without the absolute value bars:

|x|=|y||x7|=|x+3|
x=+y(x7)=(x+3)
x=y(x7)=(x+3)
+x=y(x7)=(x+3)
x=y(x7)=(x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x7|=|x+3|
x=+y , +x=y(x7)=(x+3)
x=y , x=y(x7)=(x+3)

3. Solve the two equations for x

12 additional steps

(x-7)=-(x+3)

Expand the parentheses:

(x-7)=-x-3

Add to both sides:

(x-7)+x=(-x-3)+x

Group like terms:

(x+x)-7=(-x-3)+x

Simplify the arithmetic:

2x-7=(-x-3)+x

Group like terms:

2x-7=(-x+x)-3

Simplify the arithmetic:

2x7=3

Add to both sides:

(2x-7)+7=-3+7

Simplify the arithmetic:

2x=3+7

Simplify the arithmetic:

2x=4

Divide both sides by :

(2x)2=42

Simplify the fraction:

x=42

Find the greatest common factor of the numerator and denominator:

x=(2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

6 additional steps

(x-7)=-(-(x+3))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x-7)=x+3

Subtract from both sides:

(x-7)-x=(x+3)-x

Group like terms:

(x-x)-7=(x+3)-x

Simplify the arithmetic:

-7=(x+3)-x

Group like terms:

-7=(x-x)+3

Simplify the arithmetic:

7=3

The statement is false:

7=3

The equation is false so it has no solution.

4. List the solutions

x=2
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x7|
y=|x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.