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Solution - Absolute value equations

Exact form: x=-3,32
x=-3 , \frac{3}{2}
Mixed number form: x=-3,112
x=-3 , 1\frac{1}{2}
Decimal form: x=3,1.5
x=-3 , 1.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x6|=3|x|
without the absolute value bars:

|x|=|y||x6|=3|x|
x=+y(x6)=3(x)
x=y(x6)=3((x))
+x=y(x6)=3(x)
x=y(x6)=3(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x6|=3|x|
x=+y , +x=y(x6)=3(x)
x=y , x=y(x6)=3((x))

2. Solve the two equations for x

12 additional steps

(x-6)=3x

Subtract from both sides:

(x-6)-3x=(3x)-3x

Group like terms:

(x-3x)-6=(3x)-3x

Simplify the arithmetic:

-2x-6=(3x)-3x

Simplify the arithmetic:

2x6=0

Add to both sides:

(-2x-6)+6=0+6

Simplify the arithmetic:

2x=0+6

Simplify the arithmetic:

2x=6

Divide both sides by :

(-2x)-2=6-2

Cancel out the negatives:

2x2=6-2

Simplify the fraction:

x=6-2

Move the negative sign from the denominator to the numerator:

x=-62

Find the greatest common factor of the numerator and denominator:

x=(-3·2)(1·2)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(x-6)=3·-x

Group like terms:

(x-6)=(3·-1)x

Multiply the coefficients:

(x-6)=-3x

Add to both sides:

(x-6)+3x=(-3x)+3x

Group like terms:

(x+3x)-6=(-3x)+3x

Simplify the arithmetic:

4x-6=(-3x)+3x

Simplify the arithmetic:

4x6=0

Add to both sides:

(4x-6)+6=0+6

Simplify the arithmetic:

4x=0+6

Simplify the arithmetic:

4x=6

Divide both sides by :

(4x)4=64

Simplify the fraction:

x=64

Find the greatest common factor of the numerator and denominator:

x=(3·2)(2·2)

Factor out and cancel the greatest common factor:

x=32

3. List the solutions

x=-3,32
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x6|
y=3|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.