Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=3
x=3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x5|+|x1|=0

Add |x1| to both sides of the equation:

|x5|+|x1||x1|=|x1|

Simplify the arithmetic

|x5|=|x1|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x5|=|x1|
without the absolute value bars:

|x|=|y||x5|=|x1|
x=+y(x5)=(x1)
x=y(x5)=(x1)
+x=y(x5)=(x1)
x=y(x5)=(x1)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x5|=|x1|
x=+y , +x=y(x5)=(x1)
x=y , x=y(x5)=(x1)

3. Solve the two equations for x

12 additional steps

(x-5)=-(x-1)

Expand the parentheses:

(x-5)=-x+1

Add to both sides:

(x-5)+x=(-x+1)+x

Group like terms:

(x+x)-5=(-x+1)+x

Simplify the arithmetic:

2x-5=(-x+1)+x

Group like terms:

2x-5=(-x+x)+1

Simplify the arithmetic:

2x5=1

Add to both sides:

(2x-5)+5=1+5

Simplify the arithmetic:

2x=1+5

Simplify the arithmetic:

2x=6

Divide both sides by :

(2x)2=62

Simplify the fraction:

x=62

Find the greatest common factor of the numerator and denominator:

x=(3·2)(1·2)

Factor out and cancel the greatest common factor:

x=3

6 additional steps

(x-5)=-(-(x-1))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x-5)=x-1

Subtract from both sides:

(x-5)-x=(x-1)-x

Group like terms:

(x-x)-5=(x-1)-x

Simplify the arithmetic:

-5=(x-1)-x

Group like terms:

-5=(x-x)-1

Simplify the arithmetic:

5=1

The statement is false:

5=1

The equation is false so it has no solution.

4. List the solutions

x=3
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x5|
y=|x1|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.