Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=2,1
x=-2 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x4|3|x|=0

Add 3|x| to both sides of the equation:

|x4|3|x|+3|x|=3|x|

Simplify the arithmetic

|x4|=3|x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x4|=3|x|
without the absolute value bars:

|x|=|y||x4|=3|x|
x=+y(x4)=3(x)
x=y(x4)=3((x))
+x=y(x4)=3(x)
x=y(x4)=3(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x4|=3|x|
x=+y , +x=y(x4)=3(x)
x=y , x=y(x4)=3((x))

3. Solve the two equations for x

12 additional steps

(x-4)=3x

Subtract from both sides:

(x-4)-3x=(3x)-3x

Group like terms:

(x-3x)-4=(3x)-3x

Simplify the arithmetic:

-2x-4=(3x)-3x

Simplify the arithmetic:

2x4=0

Add to both sides:

(-2x-4)+4=0+4

Simplify the arithmetic:

2x=0+4

Simplify the arithmetic:

2x=4

Divide both sides by :

(-2x)-2=4-2

Cancel out the negatives:

2x2=4-2

Simplify the fraction:

x=4-2

Move the negative sign from the denominator to the numerator:

x=-42

Find the greatest common factor of the numerator and denominator:

x=(-2·2)(1·2)

Factor out and cancel the greatest common factor:

x=2

11 additional steps

(x-4)=3·-x

Group like terms:

(x-4)=(3·-1)x

Multiply the coefficients:

(x-4)=-3x

Add to both sides:

(x-4)+3x=(-3x)+3x

Group like terms:

(x+3x)-4=(-3x)+3x

Simplify the arithmetic:

4x-4=(-3x)+3x

Simplify the arithmetic:

4x4=0

Add to both sides:

(4x-4)+4=0+4

Simplify the arithmetic:

4x=0+4

Simplify the arithmetic:

4x=4

Divide both sides by :

(4x)4=44

Simplify the fraction:

x=44

Simplify the fraction:

x=1

4. List the solutions

x=2,1
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x4|
y=3|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.