Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=34
x=\frac{3}{4}
Decimal form: x=0.75
x=0.75

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x-43|=|x-16|
without the absolute value bars:

|x|=|y||x-43|=|x-16|
x=+y(x-43)=(x-16)
x=-y(x-43)=-(x-16)
+x=y(x-43)=(x-16)
-x=y-(x-43)=(x-16)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x-43|=|x-16|
x=+y , +x=y(x-43)=(x-16)
x=-y , -x=y(x-43)=-(x-16)

2. Solve the two equations for x

5 additional steps

(x+-43)=(x+-16)

Subtract from both sides:

(x+-43)-x=(x+-16)-x

Group like terms:

(x-x)+-43=(x+-16)-x

Simplify the arithmetic:

-43=(x+-16)-x

Group like terms:

-43=(x-x)+-16

Simplify the arithmetic:

-43=-16

The statement is false:

-43=-16

The equation is false so it has no solution.

21 additional steps

(x+-43)=-(x+-16)

Expand the parentheses:

(x+-43)=-x+16

Add to both sides:

(x+-43)+x=(-x+16)+x

Group like terms:

(x+x)+-43=(-x+16)+x

Simplify the arithmetic:

2x+-43=(-x+16)+x

Group like terms:

2x+-43=(-x+x)+16

Simplify the arithmetic:

2x+-43=16

Add to both sides:

(2x+-43)+43=(16)+43

Combine the fractions:

2x+(-4+4)3=(16)+43

Combine the numerators:

2x+03=(16)+43

Reduce the zero numerator:

2x+0=(16)+43

Simplify the arithmetic:

2x=(16)+43

Find the lowest common denominator:

2x=16+(4·2)(3·2)

Multiply the denominators:

2x=16+(4·2)6

Multiply the numerators:

2x=16+86

Combine the fractions:

2x=(1+8)6

Combine the numerators:

2x=96

Find the greatest common factor of the numerator and denominator:

2x=(3·3)(2·3)

Factor out and cancel the greatest common factor:

2x=32

Divide both sides by :

(2x)2=(32)2

Simplify the fraction:

x=(32)2

Simplify the arithmetic:

x=3(2·2)

x=34

3. Graph

Each line represents the function of one side of the equation:
y=|x-43|
y=|x-16|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.