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Solution - Absolute value equations

Exact form: x=20
x=20

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x30|+|x10|=0

Add |x10| to both sides of the equation:

|x30|+|x10||x10|=|x10|

Simplify the arithmetic

|x30|=|x10|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x30|=|x10|
without the absolute value bars:

|x|=|y||x30|=|x10|
x=+y(x30)=(x10)
x=y(x30)=(x10)
+x=y(x30)=(x10)
x=y(x30)=(x10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x30|=|x10|
x=+y , +x=y(x30)=(x10)
x=y , x=y(x30)=(x10)

3. Solve the two equations for x

12 additional steps

(x-30)=-(x-10)

Expand the parentheses:

(x-30)=-x+10

Add to both sides:

(x-30)+x=(-x+10)+x

Group like terms:

(x+x)-30=(-x+10)+x

Simplify the arithmetic:

2x-30=(-x+10)+x

Group like terms:

2x-30=(-x+x)+10

Simplify the arithmetic:

2x30=10

Add to both sides:

(2x-30)+30=10+30

Simplify the arithmetic:

2x=10+30

Simplify the arithmetic:

2x=40

Divide both sides by :

(2x)2=402

Simplify the fraction:

x=402

Find the greatest common factor of the numerator and denominator:

x=(20·2)(1·2)

Factor out and cancel the greatest common factor:

x=20

6 additional steps

(x-30)=-(-(x-10))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x-30)=x-10

Subtract from both sides:

(x-30)-x=(x-10)-x

Group like terms:

(x-x)-30=(x-10)-x

Simplify the arithmetic:

-30=(x-10)-x

Group like terms:

-30=(x-x)-10

Simplify the arithmetic:

30=10

The statement is false:

30=10

The equation is false so it has no solution.

4. List the solutions

x=20
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x30|
y=|x10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.