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Solution - Absolute value equations

Exact form: x=52
x=\frac{5}{2}
Mixed number form: x=212
x=2\frac{1}{2}
Decimal form: x=2.5
x=2.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x3||x2|=0

Add |x2| to both sides of the equation:

|x3||x2|+|x2|=|x2|

Simplify the arithmetic

|x3|=|x2|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x3|=|x2|
without the absolute value bars:

|x|=|y||x3|=|x2|
x=+y(x3)=(x2)
x=y(x3)=((x2))
+x=y(x3)=(x2)
x=y(x3)=(x2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x3|=|x2|
x=+y , +x=y(x3)=(x2)
x=y , x=y(x3)=((x2))

3. Solve the two equations for x

5 additional steps

(x-3)=(x-2)

Subtract from both sides:

(x-3)-x=(x-2)-x

Group like terms:

(x-x)-3=(x-2)-x

Simplify the arithmetic:

-3=(x-2)-x

Group like terms:

-3=(x-x)-2

Simplify the arithmetic:

3=2

The statement is false:

3=2

The equation is false so it has no solution.

10 additional steps

(x-3)=-(x-2)

Expand the parentheses:

(x-3)=-x+2

Add to both sides:

(x-3)+x=(-x+2)+x

Group like terms:

(x+x)-3=(-x+2)+x

Simplify the arithmetic:

2x-3=(-x+2)+x

Group like terms:

2x-3=(-x+x)+2

Simplify the arithmetic:

2x3=2

Add to both sides:

(2x-3)+3=2+3

Simplify the arithmetic:

2x=2+3

Simplify the arithmetic:

2x=5

Divide both sides by :

(2x)2=52

Simplify the fraction:

x=52

4. Graph

Each line represents the function of one side of the equation:
y=|x3|
y=|x2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.