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Solution - Absolute value equations

Exact form: x=1,53
x=1 , \frac{5}{3}
Mixed number form: x=1,123
x=1 , 1\frac{2}{3}
Decimal form: x=1,1.667
x=1 , 1.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x3||5x7|=0

Add |5x7| to both sides of the equation:

|x3||5x7|+|5x7|=|5x7|

Simplify the arithmetic

|x3|=|5x7|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x3|=|5x7|
without the absolute value bars:

|x|=|y||x3|=|5x7|
x=+y(x3)=(5x7)
x=y(x3)=((5x7))
+x=y(x3)=(5x7)
x=y(x3)=(5x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x3|=|5x7|
x=+y , +x=y(x3)=(5x7)
x=y , x=y(x3)=((5x7))

3. Solve the two equations for x

12 additional steps

(x-3)=(5x-7)

Subtract from both sides:

(x-3)-5x=(5x-7)-5x

Group like terms:

(x-5x)-3=(5x-7)-5x

Simplify the arithmetic:

-4x-3=(5x-7)-5x

Group like terms:

-4x-3=(5x-5x)-7

Simplify the arithmetic:

4x3=7

Add to both sides:

(-4x-3)+3=-7+3

Simplify the arithmetic:

4x=7+3

Simplify the arithmetic:

4x=4

Divide both sides by :

(-4x)-4=-4-4

Cancel out the negatives:

4x4=-4-4

Simplify the fraction:

x=-4-4

Cancel out the negatives:

x=44

Simplify the fraction:

x=1

12 additional steps

(x-3)=-(5x-7)

Expand the parentheses:

(x-3)=-5x+7

Add to both sides:

(x-3)+5x=(-5x+7)+5x

Group like terms:

(x+5x)-3=(-5x+7)+5x

Simplify the arithmetic:

6x-3=(-5x+7)+5x

Group like terms:

6x-3=(-5x+5x)+7

Simplify the arithmetic:

6x3=7

Add to both sides:

(6x-3)+3=7+3

Simplify the arithmetic:

6x=7+3

Simplify the arithmetic:

6x=10

Divide both sides by :

(6x)6=106

Simplify the fraction:

x=106

Find the greatest common factor of the numerator and denominator:

x=(5·2)(3·2)

Factor out and cancel the greatest common factor:

x=53

4. List the solutions

x=1,53
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x3|
y=|5x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.