Enter an equation or problem

Camera input is not recognized!

Solution - Absolute value equations

Exact form:

x = \frac{4025}{2}

x=\frac{4025}{2}

Mixed number form:

x = 2012 \frac{1}{2}

x=2012\frac{1}{2}

Decimal form:

x = 2012.5

x=2012.5

See steps

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

$| x - 2012 | + | x - 2013 | = 0$

Add $- | x - 2013 |$ to both sides of the equation:

$| x - 2012 | + | x - 2013 | - | x - 2013 | = - | x - 2013 |$

Simplify the arithmetic

$| x - 2012 | = - | x - 2013 |$

2. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| x - 2012 | = - | x - 2013 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| x - 2012 \| = - \| x - 2013 \|$
$x = + y$	$(x - 2012) = - (x - 2013)$
$x = - y$	$(x - 2012) = - - (x - 2013)$
$+ x = y$	$(x - 2012) = - (x - 2013)$
$- x = y$	$- (x - 2012) = - (x - 2013)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| x - 2012 \| = - \| x - 2013 \|$
$x = + y$ , $+ x = y$	$(x - 2012) = - (x - 2013)$
$x = - y$ , $- x = y$	$(x - 2012) = - - (x - 2013)$

3. Solve the two equations for x

10 additional steps

$(x - 2012) = - (x - 2013)$

Expand the parentheses:

$(x - 2012) = - x + 2013$

Add to both sides:

$(x - 2012) + x = (- x + 2013) + x$

Group like terms:

$(x + x) - 2012 = (- x + 2013) + x$

Simplify the arithmetic:

$2 x - 2012 = (- x + 2013) + x$

Group like terms:

$2 x - 2012 = (- x + x) + 2013$

Simplify the arithmetic:

$2 x - 2012 = 2013$

Add to both sides:

$(2 x - 2012) + 2012 = 2013 + 2012$

Simplify the arithmetic:

$2 x = 2013 + 2012$

Simplify the arithmetic:

$2 x = 4025$

Divide both sides by :

$\frac{(2 x)}{2} = \frac{4025}{2}$

Simplify the fraction:

$x = \frac{4025}{2}$

6 additional steps

$(x - 2012) = - (- (x - 2013))$

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

$(x - 2012) = x - 2013$

Subtract from both sides:

$(x - 2012) - x = (x - 2013) - x$

Group like terms:

$(x - x) - 2012 = (x - 2013) - x$

Simplify the arithmetic:

$- 2012 = (x - 2013) - x$

Group like terms:

$- 2012 = (x - x) - 2013$

Simplify the arithmetic:

$- 2012 = - 2013$

The statement is false:

$- 2012 = - 2013$

The equation is false so it has no solution.

4. List the solutions

$x = \frac{4025}{2}$
(1 solution(s))

5. Graph

Each line represents the function of one side of the equation:
$y = | x - 2012 |$
$y = - | x - 2013 |$
The equation is true where the two lines cross.

How did we do?

Please leave us feedback.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved