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Solution - Absolute value equations

Exact form:

x = \frac{1}{2}, \frac{5}{4}

x=\frac{1}{2} , \frac{5}{4}

Mixed number form:

x = \frac{1}{2}, 1 \frac{1}{4}

x=\frac{1}{2} , 1\frac{1}{4}

Decimal form:

x = 0.5, 1.25

x=0.5 , 1.25

See steps

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

$| x - 2 | - 3 | x - 1 | = 0$

Add $3 | x - 1 |$ to both sides of the equation:

$| x - 2 | - 3 | x - 1 | + 3 | x - 1 | = 3 | x - 1 |$

Simplify the arithmetic

$| x - 2 | = 3 | x - 1 |$

2. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| x - 2 | = 3 | x - 1 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| x - 2 \| = 3 \| x - 1 \|$
$x = + y$	$(x - 2) = 3 (x - 1)$
$x = - y$	$(x - 2) = 3 (- (x - 1))$
$+ x = y$	$(x - 2) = 3 (x - 1)$
$- x = y$	$- (x - 2) = 3 (x - 1)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| x - 2 \| = 3 \| x - 1 \|$
$x = + y$ , $+ x = y$	$(x - 2) = 3 (x - 1)$
$x = - y$ , $- x = y$	$(x - 2) = 3 (- (x - 1))$

3. Solve the two equations for x

13 additional steps

$(x - 2) = 3 \cdot (x - 1)$

Expand the parentheses:

$(x - 2) = 3 x + 3 \cdot - 1$

Simplify the arithmetic:

$(x - 2) = 3 x - 3$

Subtract from both sides:

$(x - 2) - 3 x = (3 x - 3) - 3 x$

Group like terms:

$(x - 3 x) - 2 = (3 x - 3) - 3 x$

Simplify the arithmetic:

$- 2 x - 2 = (3 x - 3) - 3 x$

Group like terms:

$- 2 x - 2 = (3 x - 3 x) - 3$

Simplify the arithmetic:

$- 2 x - 2 = - 3$

Add to both sides:

$(- 2 x - 2) + 2 = - 3 + 2$

Simplify the arithmetic:

$- 2 x = - 3 + 2$

Simplify the arithmetic:

$- 2 x = - 1$

Divide both sides by :

$\frac{(- 2 x)}{- 2} = \frac{- 1}{- 2}$

Cancel out the negatives:

$\frac{2 x}{2} = \frac{- 1}{- 2}$

Simplify the fraction:

$x = \frac{- 1}{- 2}$

Cancel out the negatives:

$x = \frac{1}{2}$

14 additional steps

$(x - 2) = 3 \cdot (- (x - 1))$

Expand the parentheses:

$(x - 2) = 3 \cdot (- x + 1)$

$(x - 2) = 3 \cdot - x + 3 \cdot 1$

Group like terms:

$(x - 2) = (3 \cdot - 1) x + 3 \cdot 1$

Multiply the coefficients:

$(x - 2) = - 3 x + 3 \cdot 1$

Simplify the arithmetic:

$(x - 2) = - 3 x + 3$

Add to both sides:

$(x - 2) + 3 x = (- 3 x + 3) + 3 x$

Group like terms:

$(x + 3 x) - 2 = (- 3 x + 3) + 3 x$

Simplify the arithmetic:

$4 x - 2 = (- 3 x + 3) + 3 x$

Group like terms:

$4 x - 2 = (- 3 x + 3 x) + 3$

Simplify the arithmetic:

$4 x - 2 = 3$

Add to both sides:

$(4 x - 2) + 2 = 3 + 2$

Simplify the arithmetic:

$4 x = 3 + 2$

Simplify the arithmetic:

$4 x = 5$

Divide both sides by :

$\frac{(4 x)}{4} = \frac{5}{4}$

Simplify the fraction:

$x = \frac{5}{4}$

4. List the solutions

$x = \frac{1}{2}, \frac{5}{4}$
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
$y = | x - 2 |$
$y = 3 | x - 1 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

2. Rewrite the equation without absolute value bars

3. Solve the two equations for x

4. List the solutions

5. Graph

Why learn this

Terms and topics

Related links

Latest Related Drills Solved