Enter an equation or problem
Camera input is not recognized!

Solution - Absolute value equations

Exact form: x=53,1
x=\frac{5}{3} , 1
Mixed number form: x=123,1
x=1\frac{2}{3} , 1
Decimal form: x=1.667,1
x=1.667 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x2|=|2x+3|
without the absolute value bars:

|x|=|y||x2|=|2x+3|
x=+y(x2)=(2x+3)
x=y(x2)=(2x+3)
+x=y(x2)=(2x+3)
x=y(x2)=(2x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x2|=|2x+3|
x=+y , +x=y(x2)=(2x+3)
x=y , x=y(x2)=(2x+3)

2. Solve the two equations for x

9 additional steps

(x-2)=(-2x+3)

Add to both sides:

(x-2)+2x=(-2x+3)+2x

Group like terms:

(x+2x)-2=(-2x+3)+2x

Simplify the arithmetic:

3x-2=(-2x+3)+2x

Group like terms:

3x-2=(-2x+2x)+3

Simplify the arithmetic:

3x2=3

Add to both sides:

(3x-2)+2=3+2

Simplify the arithmetic:

3x=3+2

Simplify the arithmetic:

3x=5

Divide both sides by :

(3x)3=53

Simplify the fraction:

x=53

11 additional steps

(x-2)=-(-2x+3)

Expand the parentheses:

(x-2)=2x-3

Subtract from both sides:

(x-2)-2x=(2x-3)-2x

Group like terms:

(x-2x)-2=(2x-3)-2x

Simplify the arithmetic:

-x-2=(2x-3)-2x

Group like terms:

-x-2=(2x-2x)-3

Simplify the arithmetic:

x2=3

Add to both sides:

(-x-2)+2=-3+2

Simplify the arithmetic:

x=3+2

Simplify the arithmetic:

x=1

Multiply both sides by :

-x·-1=-1·-1

Remove the one(s):

x=-1·-1

Simplify the arithmetic:

x=1

3. List the solutions

x=53,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x2|
y=|2x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.