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Solution - Absolute value equations

Exact form: x=-13,-5
x=-\frac{1}{3} , -5
Decimal form: x=0.333,5
x=-0.333 , -5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x2|+|2x+3|=0

Add |2x+3| to both sides of the equation:

|x2|+|2x+3||2x+3|=|2x+3|

Simplify the arithmetic

|x2|=|2x+3|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x2|=|2x+3|
without the absolute value bars:

|x|=|y||x2|=|2x+3|
x=+y(x2)=(2x+3)
x=y(x2)=(2x+3)
+x=y(x2)=(2x+3)
x=y(x2)=(2x+3)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x2|=|2x+3|
x=+y , +x=y(x2)=(2x+3)
x=y , x=y(x2)=(2x+3)

3. Solve the two equations for x

10 additional steps

(x-2)=-(2x+3)

Expand the parentheses:

(x-2)=-2x-3

Add to both sides:

(x-2)+2x=(-2x-3)+2x

Group like terms:

(x+2x)-2=(-2x-3)+2x

Simplify the arithmetic:

3x-2=(-2x-3)+2x

Group like terms:

3x-2=(-2x+2x)-3

Simplify the arithmetic:

3x2=3

Add to both sides:

(3x-2)+2=-3+2

Simplify the arithmetic:

3x=3+2

Simplify the arithmetic:

3x=1

Divide both sides by :

(3x)3=-13

Simplify the fraction:

x=-13

11 additional steps

(x-2)=-(-(2x+3))

NT_MSLUS_MAINSTEP_RESOLVE_DOUBLE_MINUS:

(x-2)=2x+3

Subtract from both sides:

(x-2)-2x=(2x+3)-2x

Group like terms:

(x-2x)-2=(2x+3)-2x

Simplify the arithmetic:

-x-2=(2x+3)-2x

Group like terms:

-x-2=(2x-2x)+3

Simplify the arithmetic:

x2=3

Add to both sides:

(-x-2)+2=3+2

Simplify the arithmetic:

x=3+2

Simplify the arithmetic:

x=5

Multiply both sides by :

-x·-1=5·-1

Remove the one(s):

x=5·-1

Simplify the arithmetic:

x=5

4. List the solutions

x=-13,-5
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x2|
y=|2x+3|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.