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Solution - Absolute value equations

Exact form:

x = \frac{5}{11}, \frac{5}{13}

x=\frac{5}{11} , \frac{5}{13}

Decimal form:

x = 0.455, 0.385

x=0.455 , 0.385

See steps

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
$| x | = | y |$ → $x = \pm y$ and $| x | = | y |$ → $\pm x = y$
to write all four options of the equation
$| x | = | 12 x - 5 |$
without the absolute value bars:

$\| x \| = \| y \|$	$\| x \| = \| 12 x - 5 \|$
$x = + y$	$(x) = (12 x - 5)$
$x = - y$	$(x) = - (12 x - 5)$
$+ x = y$	$(x) = (12 x - 5)$
$- x = y$	$- (x) = (12 x - 5)$

When simplified, equations $x = + y$ and $+ x = y$ are the same and equations $x = - y$ and $- x = y$ are the same, so we end up with only 2 equations:

$\| x \| = \| y \|$	$\| x \| = \| 12 x - 5 \|$
$x = + y$ , $+ x = y$	$(x) = (12 x - 5)$
$x = - y$ , $- x = y$	$(x) = - (12 x - 5)$

2. Solve the two equations for x

7 additional steps

$x = (12 x - 5)$

Subtract from both sides:

$x - 12 x = (12 x - 5) - 12 x$

Simplify the arithmetic:

$- 11 x = (12 x - 5) - 12 x$

Group like terms:

$- 11 x = (12 x - 12 x) - 5$

Simplify the arithmetic:

$- 11 x = - 5$

Divide both sides by :

$\frac{(- 11 x)}{- 11} = \frac{- 5}{- 11}$

Cancel out the negatives:

$\frac{11 x}{11} = \frac{- 5}{- 11}$

Simplify the fraction:

$x = \frac{- 5}{- 11}$

Cancel out the negatives:

$x = \frac{5}{11}$

6 additional steps

$x = - (12 x - 5)$

Expand the parentheses:

$x = - 12 x + 5$

Add to both sides:

$x + 12 x = (- 12 x + 5) + 12 x$

Simplify the arithmetic:

$13 x = (- 12 x + 5) + 12 x$

Group like terms:

$13 x = (- 12 x + 12 x) + 5$

Simplify the arithmetic:

$13 x = 5$

Divide both sides by :

$\frac{(13 x)}{13} = \frac{5}{13}$

Simplify the fraction:

$x = \frac{5}{13}$

3. List the solutions

$x = \frac{5}{11}, \frac{5}{13}$
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
$y = | x |$
$y = | 12 x - 5 |$
The equation is true where the two lines cross.

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Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

Solution - Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

2. Solve the two equations for x

3. List the solutions

4. Graph

Why learn this

Terms and topics

Related links

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