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Solution - Absolute value equations

Exact form: x=611,413
x=\frac{6}{11} , \frac{4}{13}
Decimal form: x=0.545,0.308
x=0.545 , 0.308

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+1|=|12x5|
without the absolute value bars:

|x|=|y||x+1|=|12x5|
x=+y(x+1)=(12x5)
x=y(x+1)=(12x5)
+x=y(x+1)=(12x5)
x=y(x+1)=(12x5)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+1|=|12x5|
x=+y , +x=y(x+1)=(12x5)
x=y , x=y(x+1)=(12x5)

2. Solve the two equations for x

11 additional steps

(x+1)=(12x-5)

Subtract from both sides:

(x+1)-12x=(12x-5)-12x

Group like terms:

(x-12x)+1=(12x-5)-12x

Simplify the arithmetic:

-11x+1=(12x-5)-12x

Group like terms:

-11x+1=(12x-12x)-5

Simplify the arithmetic:

11x+1=5

Subtract from both sides:

(-11x+1)-1=-5-1

Simplify the arithmetic:

11x=51

Simplify the arithmetic:

11x=6

Divide both sides by :

(-11x)-11=-6-11

Cancel out the negatives:

11x11=-6-11

Simplify the fraction:

x=-6-11

Cancel out the negatives:

x=611

10 additional steps

(x+1)=-(12x-5)

Expand the parentheses:

(x+1)=-12x+5

Add to both sides:

(x+1)+12x=(-12x+5)+12x

Group like terms:

(x+12x)+1=(-12x+5)+12x

Simplify the arithmetic:

13x+1=(-12x+5)+12x

Group like terms:

13x+1=(-12x+12x)+5

Simplify the arithmetic:

13x+1=5

Subtract from both sides:

(13x+1)-1=5-1

Simplify the arithmetic:

13x=51

Simplify the arithmetic:

13x=4

Divide both sides by :

(13x)13=413

Simplify the fraction:

x=413

3. List the solutions

x=611,413
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+1|
y=|12x5|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.