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Solution - Absolute value equations

Exact form: x=63,21
x=-63 , 21

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x63|=|2x|
without the absolute value bars:

|x|=|y||x63|=|2x|
x=+y(x63)=(2x)
x=y(x63)=(2x)
+x=y(x63)=(2x)
x=y(x63)=(2x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x63|=|2x|
x=+y , +x=y(x63)=(2x)
x=y , x=y(x63)=(2x)

2. Solve the two equations for x

9 additional steps

(x-63)=2x

Subtract from both sides:

(x-63)-2x=(2x)-2x

Group like terms:

(x-2x)-63=(2x)-2x

Simplify the arithmetic:

-x-63=(2x)-2x

Simplify the arithmetic:

x63=0

Add to both sides:

(-x-63)+63=0+63

Simplify the arithmetic:

x=0+63

Simplify the arithmetic:

x=63

Multiply both sides by :

-x·-1=63·-1

Remove the one(s):

x=63·-1

Simplify the arithmetic:

x=63

9 additional steps

(x-63)=-2x

Add to both sides:

(x-63)+63=(-2x)+63

Simplify the arithmetic:

x=(-2x)+63

Add to both sides:

x+2x=((-2x)+63)+2x

Simplify the arithmetic:

3x=((-2x)+63)+2x

Group like terms:

3x=(-2x+2x)+63

Simplify the arithmetic:

3x=63

Divide both sides by :

(3x)3=633

Simplify the fraction:

x=633

Find the greatest common factor of the numerator and denominator:

x=(21·3)(1·3)

Factor out and cancel the greatest common factor:

x=21

3. List the solutions

x=63,21
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x63|
y=|2x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.