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Solution - Absolute value equations

Exact form: x=-32,1
x=-\frac{3}{2} , 1
Mixed number form: x=-112,1
x=-1\frac{1}{2} , 1
Decimal form: x=1.5,1
x=-1.5 , 1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x6|=|5x|
without the absolute value bars:

|x|=|y||x6|=|5x|
x=+y(x6)=(5x)
x=y(x6)=(5x)
+x=y(x6)=(5x)
x=y(x6)=(5x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x6|=|5x|
x=+y , +x=y(x6)=(5x)
x=y , x=y(x6)=(5x)

2. Solve the two equations for x

12 additional steps

(x-6)=5x

Subtract from both sides:

(x-6)-5x=(5x)-5x

Group like terms:

(x-5x)-6=(5x)-5x

Simplify the arithmetic:

-4x-6=(5x)-5x

Simplify the arithmetic:

4x6=0

Add to both sides:

(-4x-6)+6=0+6

Simplify the arithmetic:

4x=0+6

Simplify the arithmetic:

4x=6

Divide both sides by :

(-4x)-4=6-4

Cancel out the negatives:

4x4=6-4

Simplify the fraction:

x=6-4

Move the negative sign from the denominator to the numerator:

x=-64

Find the greatest common factor of the numerator and denominator:

x=(-3·2)(2·2)

Factor out and cancel the greatest common factor:

x=-32

8 additional steps

(x-6)=-5x

Add to both sides:

(x-6)+6=(-5x)+6

Simplify the arithmetic:

x=(-5x)+6

Add to both sides:

x+5x=((-5x)+6)+5x

Simplify the arithmetic:

6x=((-5x)+6)+5x

Group like terms:

6x=(-5x+5x)+6

Simplify the arithmetic:

6x=6

Divide both sides by :

(6x)6=66

Simplify the fraction:

x=66

Simplify the fraction:

x=1

3. List the solutions

x=-32,1
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x6|
y=|5x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.