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Solution - Absolute value equations

Exact form: x=32,73
x=\frac{3}{2} , \frac{7}{3}
Mixed number form: x=112,213
x=1\frac{1}{2} , 2\frac{1}{3}
Decimal form: x=1.5,2.333
x=1.5 , 2.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x4|=|5x10|
without the absolute value bars:

|x|=|y||x4|=|5x10|
x=+y(x4)=(5x10)
x=y(x4)=(5x10)
+x=y(x4)=(5x10)
x=y(x4)=(5x10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x4|=|5x10|
x=+y , +x=y(x4)=(5x10)
x=y , x=y(x4)=(5x10)

2. Solve the two equations for x

13 additional steps

(x-4)=(5x-10)

Subtract from both sides:

(x-4)-5x=(5x-10)-5x

Group like terms:

(x-5x)-4=(5x-10)-5x

Simplify the arithmetic:

-4x-4=(5x-10)-5x

Group like terms:

-4x-4=(5x-5x)-10

Simplify the arithmetic:

4x4=10

Add to both sides:

(-4x-4)+4=-10+4

Simplify the arithmetic:

4x=10+4

Simplify the arithmetic:

4x=6

Divide both sides by :

(-4x)-4=-6-4

Cancel out the negatives:

4x4=-6-4

Simplify the fraction:

x=-6-4

Cancel out the negatives:

x=64

Find the greatest common factor of the numerator and denominator:

x=(3·2)(2·2)

Factor out and cancel the greatest common factor:

x=32

12 additional steps

(x-4)=-(5x-10)

Expand the parentheses:

(x-4)=-5x+10

Add to both sides:

(x-4)+5x=(-5x+10)+5x

Group like terms:

(x+5x)-4=(-5x+10)+5x

Simplify the arithmetic:

6x-4=(-5x+10)+5x

Group like terms:

6x-4=(-5x+5x)+10

Simplify the arithmetic:

6x4=10

Add to both sides:

(6x-4)+4=10+4

Simplify the arithmetic:

6x=10+4

Simplify the arithmetic:

6x=14

Divide both sides by :

(6x)6=146

Simplify the fraction:

x=146

Find the greatest common factor of the numerator and denominator:

x=(7·2)(3·2)

Factor out and cancel the greatest common factor:

x=73

3. List the solutions

x=32,73
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x4|
y=|5x10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.