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Solution - Absolute value equations

Exact form: x=-15,353
x=-15 , \frac{35}{3}
Mixed number form: x=-15,1123
x=-15 , 11\frac{2}{3}
Decimal form: x=15,11.667
x=-15 , 11.667

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x25||2x10|=0

Add |2x10| to both sides of the equation:

|x25||2x10|+|2x10|=|2x10|

Simplify the arithmetic

|x25|=|2x10|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x25|=|2x10|
without the absolute value bars:

|x|=|y||x25|=|2x10|
x=+y(x25)=(2x10)
x=y(x25)=((2x10))
+x=y(x25)=(2x10)
x=y(x25)=(2x10)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x25|=|2x10|
x=+y , +x=y(x25)=(2x10)
x=y , x=y(x25)=((2x10))

3. Solve the two equations for x

10 additional steps

(x-25)=(2x-10)

Subtract from both sides:

(x-25)-2x=(2x-10)-2x

Group like terms:

(x-2x)-25=(2x-10)-2x

Simplify the arithmetic:

-x-25=(2x-10)-2x

Group like terms:

-x-25=(2x-2x)-10

Simplify the arithmetic:

x25=10

Add to both sides:

(-x-25)+25=-10+25

Simplify the arithmetic:

x=10+25

Simplify the arithmetic:

x=15

Multiply both sides by :

-x·-1=15·-1

Remove the one(s):

x=15·-1

Simplify the arithmetic:

x=15

10 additional steps

(x-25)=-(2x-10)

Expand the parentheses:

(x-25)=-2x+10

Add to both sides:

(x-25)+2x=(-2x+10)+2x

Group like terms:

(x+2x)-25=(-2x+10)+2x

Simplify the arithmetic:

3x-25=(-2x+10)+2x

Group like terms:

3x-25=(-2x+2x)+10

Simplify the arithmetic:

3x25=10

Add to both sides:

(3x-25)+25=10+25

Simplify the arithmetic:

3x=10+25

Simplify the arithmetic:

3x=35

Divide both sides by :

(3x)3=353

Simplify the fraction:

x=353

4. List the solutions

x=-15,353
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x25|
y=|2x10|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.