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Solution - Absolute value equations

Exact form: x=6
x=6

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x12||x|=0

Add |x| to both sides of the equation:

|x12||x|+|x|=|x|

Simplify the arithmetic

|x12|=|x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x12|=|x|
without the absolute value bars:

|x|=|y||x12|=|x|
x=+y(x12)=(x)
x=y(x12)=((x))
+x=y(x12)=(x)
x=y(x12)=(x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x12|=|x|
x=+y , +x=y(x12)=(x)
x=y , x=y(x12)=((x))

3. Solve the two equations for x

4 additional steps

(x-12)=x

Subtract from both sides:

(x-12)-x=x-x

Group like terms:

(x-x)-12=x-x

Simplify the arithmetic:

12=xx

Simplify the arithmetic:

12=0

The statement is false:

12=0

The equation is false so it has no solution.

10 additional steps

(x-12)=-x

Add to both sides:

(x-12)+x=-x+x

Group like terms:

(x+x)-12=-x+x

Simplify the arithmetic:

2x12=x+x

Simplify the arithmetic:

2x12=0

Add to both sides:

(2x-12)+12=0+12

Simplify the arithmetic:

2x=0+12

Simplify the arithmetic:

2x=12

Divide both sides by :

(2x)2=122

Simplify the fraction:

x=122

Find the greatest common factor of the numerator and denominator:

x=(6·2)(1·2)

Factor out and cancel the greatest common factor:

x=6

4. Graph

Each line represents the function of one side of the equation:
y=|x12|
y=|x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.