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Solution - Absolute value equations

Exact form: x=32,-1
x=\frac{3}{2} , -1
Mixed number form: x=112,-1
x=1\frac{1}{2} , -1
Decimal form: x=1.5,1
x=1.5 , -1

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation with one absolute value terms on each side

|x+6||5x|=0

Add |5x| to both sides of the equation:

|x+6||5x|+|5x|=|5x|

Simplify the arithmetic

|x+6|=|5x|

2. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+6|=|5x|
without the absolute value bars:

|x|=|y||x+6|=|5x|
x=+y(x+6)=(5x)
x=y(x+6)=((5x))
+x=y(x+6)=(5x)
x=y(x+6)=(5x)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+6|=|5x|
x=+y , +x=y(x+6)=(5x)
x=y , x=y(x+6)=((5x))

3. Solve the two equations for x

12 additional steps

(x+6)=5x

Subtract from both sides:

(x+6)-5x=(5x)-5x

Group like terms:

(x-5x)+6=(5x)-5x

Simplify the arithmetic:

-4x+6=(5x)-5x

Simplify the arithmetic:

4x+6=0

Subtract from both sides:

(-4x+6)-6=0-6

Simplify the arithmetic:

4x=06

Simplify the arithmetic:

4x=6

Divide both sides by :

(-4x)-4=-6-4

Cancel out the negatives:

4x4=-6-4

Simplify the fraction:

x=-6-4

Cancel out the negatives:

x=64

Find the greatest common factor of the numerator and denominator:

x=(3·2)(2·2)

Factor out and cancel the greatest common factor:

x=32

8 additional steps

(x+6)=-5x

Subtract from both sides:

(x+6)-6=(-5x)-6

Simplify the arithmetic:

x=(-5x)-6

Add to both sides:

x+5x=((-5x)-6)+5x

Simplify the arithmetic:

6x=((-5x)-6)+5x

Group like terms:

6x=(-5x+5x)-6

Simplify the arithmetic:

6x=6

Divide both sides by :

(6x)6=-66

Simplify the fraction:

x=-66

Simplify the fraction:

x=1

4. List the solutions

x=32,-1
(2 solution(s))

5. Graph

Each line represents the function of one side of the equation:
y=|x+6|
y=|5x|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.