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Solution - Absolute value equations

Exact form: x=74,-116
x=\frac{7}{4} , -\frac{11}{6}
Mixed number form: x=134,-156
x=1\frac{3}{4} , -1\frac{5}{6}
Decimal form: x=1.75,1.833
x=1.75 , -1.833

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+9|=|5x+2|
without the absolute value bars:

|x|=|y||x+9|=|5x+2|
x=+y(x+9)=(5x+2)
x=y(x+9)=(5x+2)
+x=y(x+9)=(5x+2)
x=y(x+9)=(5x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+9|=|5x+2|
x=+y , +x=y(x+9)=(5x+2)
x=y , x=y(x+9)=(5x+2)

2. Solve the two equations for x

11 additional steps

(x+9)=(5x+2)

Subtract from both sides:

(x+9)-5x=(5x+2)-5x

Group like terms:

(x-5x)+9=(5x+2)-5x

Simplify the arithmetic:

-4x+9=(5x+2)-5x

Group like terms:

-4x+9=(5x-5x)+2

Simplify the arithmetic:

4x+9=2

Subtract from both sides:

(-4x+9)-9=2-9

Simplify the arithmetic:

4x=29

Simplify the arithmetic:

4x=7

Divide both sides by :

(-4x)-4=-7-4

Cancel out the negatives:

4x4=-7-4

Simplify the fraction:

x=-7-4

Cancel out the negatives:

x=74

10 additional steps

(x+9)=-(5x+2)

Expand the parentheses:

(x+9)=-5x-2

Add to both sides:

(x+9)+5x=(-5x-2)+5x

Group like terms:

(x+5x)+9=(-5x-2)+5x

Simplify the arithmetic:

6x+9=(-5x-2)+5x

Group like terms:

6x+9=(-5x+5x)-2

Simplify the arithmetic:

6x+9=2

Subtract from both sides:

(6x+9)-9=-2-9

Simplify the arithmetic:

6x=29

Simplify the arithmetic:

6x=11

Divide both sides by :

(6x)6=-116

Simplify the fraction:

x=-116

3. List the solutions

x=74,-116
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+9|
y=|5x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.