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Solution - Absolute value equations

Exact form: x=15,92
x=15 , \frac{9}{2}
Mixed number form: x=15,412
x=15 , 4\frac{1}{2}
Decimal form: x=15,4.5
x=15 , 4.5

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+6|=|3x24|
without the absolute value bars:

|x|=|y||x+6|=|3x24|
x=+y(x+6)=(3x24)
x=y(x+6)=(3x24)
+x=y(x+6)=(3x24)
x=y(x+6)=(3x24)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+6|=|3x24|
x=+y , +x=y(x+6)=(3x24)
x=y , x=y(x+6)=(3x24)

2. Solve the two equations for x

13 additional steps

(x+6)=(3x-24)

Subtract from both sides:

(x+6)-3x=(3x-24)-3x

Group like terms:

(x-3x)+6=(3x-24)-3x

Simplify the arithmetic:

-2x+6=(3x-24)-3x

Group like terms:

-2x+6=(3x-3x)-24

Simplify the arithmetic:

2x+6=24

Subtract from both sides:

(-2x+6)-6=-24-6

Simplify the arithmetic:

2x=246

Simplify the arithmetic:

2x=30

Divide both sides by :

(-2x)-2=-30-2

Cancel out the negatives:

2x2=-30-2

Simplify the fraction:

x=-30-2

Cancel out the negatives:

x=302

Find the greatest common factor of the numerator and denominator:

x=(15·2)(1·2)

Factor out and cancel the greatest common factor:

x=15

12 additional steps

(x+6)=-(3x-24)

Expand the parentheses:

(x+6)=-3x+24

Add to both sides:

(x+6)+3x=(-3x+24)+3x

Group like terms:

(x+3x)+6=(-3x+24)+3x

Simplify the arithmetic:

4x+6=(-3x+24)+3x

Group like terms:

4x+6=(-3x+3x)+24

Simplify the arithmetic:

4x+6=24

Subtract from both sides:

(4x+6)-6=24-6

Simplify the arithmetic:

4x=246

Simplify the arithmetic:

4x=18

Divide both sides by :

(4x)4=184

Simplify the fraction:

x=184

Find the greatest common factor of the numerator and denominator:

x=(9·2)(2·2)

Factor out and cancel the greatest common factor:

x=92

3. List the solutions

x=15,92
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+6|
y=|3x24|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.