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Solution - Absolute value equations

Exact form: x=25,10
x=25 , 10

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+5|=3|x15|
without the absolute value bars:

|x|=|y||x+5|=3|x15|
x=+y(x+5)=3(x15)
x=y(x+5)=3((x15))
+x=y(x+5)=3(x15)
x=y(x+5)=3(x15)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+5|=3|x15|
x=+y , +x=y(x+5)=3(x15)
x=y , x=y(x+5)=3((x15))

2. Solve the two equations for x

15 additional steps

(x+5)=3·(x-15)

Expand the parentheses:

(x+5)=3x+3·-15

Simplify the arithmetic:

(x+5)=3x-45

Subtract from both sides:

(x+5)-3x=(3x-45)-3x

Group like terms:

(x-3x)+5=(3x-45)-3x

Simplify the arithmetic:

-2x+5=(3x-45)-3x

Group like terms:

-2x+5=(3x-3x)-45

Simplify the arithmetic:

2x+5=45

Subtract from both sides:

(-2x+5)-5=-45-5

Simplify the arithmetic:

2x=455

Simplify the arithmetic:

2x=50

Divide both sides by :

(-2x)-2=-50-2

Cancel out the negatives:

2x2=-50-2

Simplify the fraction:

x=-50-2

Cancel out the negatives:

x=502

Find the greatest common factor of the numerator and denominator:

x=(25·2)(1·2)

Factor out and cancel the greatest common factor:

x=25

16 additional steps

(x+5)=3·(-(x-15))

Expand the parentheses:

(x+5)=3·(-x+15)

(x+5)=3·-x+3·15

Group like terms:

(x+5)=(3·-1)x+3·15

Multiply the coefficients:

(x+5)=-3x+3·15

Simplify the arithmetic:

(x+5)=-3x+45

Add to both sides:

(x+5)+3x=(-3x+45)+3x

Group like terms:

(x+3x)+5=(-3x+45)+3x

Simplify the arithmetic:

4x+5=(-3x+45)+3x

Group like terms:

4x+5=(-3x+3x)+45

Simplify the arithmetic:

4x+5=45

Subtract from both sides:

(4x+5)-5=45-5

Simplify the arithmetic:

4x=455

Simplify the arithmetic:

4x=40

Divide both sides by :

(4x)4=404

Simplify the fraction:

x=404

Find the greatest common factor of the numerator and denominator:

x=(10·4)(1·4)

Factor out and cancel the greatest common factor:

x=10

3. List the solutions

x=25,10
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+5|
y=3|x15|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.