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Solution - Absolute value equations

Exact form: x=1,3
x=1 , -3

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+5|=2|x+2|
without the absolute value bars:

|x|=|y||x+5|=2|x+2|
x=+y(x+5)=2(x+2)
x=y(x+5)=2((x+2))
+x=y(x+5)=2(x+2)
x=y(x+5)=2(x+2)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+5|=2|x+2|
x=+y , +x=y(x+5)=2(x+2)
x=y , x=y(x+5)=2((x+2))

2. Solve the two equations for x

12 additional steps

(x+5)=2·(x+2)

Expand the parentheses:

(x+5)=2x+2·2

Simplify the arithmetic:

(x+5)=2x+4

Subtract from both sides:

(x+5)-2x=(2x+4)-2x

Group like terms:

(x-2x)+5=(2x+4)-2x

Simplify the arithmetic:

-x+5=(2x+4)-2x

Group like terms:

-x+5=(2x-2x)+4

Simplify the arithmetic:

x+5=4

Subtract from both sides:

(-x+5)-5=4-5

Simplify the arithmetic:

x=45

Simplify the arithmetic:

x=1

Multiply both sides by :

-x·-1=-1·-1

Remove the one(s):

x=-1·-1

Simplify the arithmetic:

x=1

16 additional steps

(x+5)=2·(-(x+2))

Expand the parentheses:

(x+5)=2·(-x-2)

(x+5)=2·-x+2·-2

Group like terms:

(x+5)=(2·-1)x+2·-2

Multiply the coefficients:

(x+5)=-2x+2·-2

Simplify the arithmetic:

(x+5)=-2x-4

Add to both sides:

(x+5)+2x=(-2x-4)+2x

Group like terms:

(x+2x)+5=(-2x-4)+2x

Simplify the arithmetic:

3x+5=(-2x-4)+2x

Group like terms:

3x+5=(-2x+2x)-4

Simplify the arithmetic:

3x+5=4

Subtract from both sides:

(3x+5)-5=-4-5

Simplify the arithmetic:

3x=45

Simplify the arithmetic:

3x=9

Divide both sides by :

(3x)3=-93

Simplify the fraction:

x=-93

Find the greatest common factor of the numerator and denominator:

x=(-3·3)(1·3)

Factor out and cancel the greatest common factor:

x=3

3. List the solutions

x=1,3
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+5|
y=2|x+2|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.