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Solution - Absolute value equations

Exact form: x=32,-18
x=\frac{3}{2} , -\frac{1}{8}
Mixed number form: x=112,-18
x=1\frac{1}{2} , -\frac{1}{8}
Decimal form: x=1.5,0.125
x=1.5 , -0.125

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+5|=|7x4|
without the absolute value bars:

|x|=|y||x+5|=|7x4|
x=+y(x+5)=(7x4)
x=y(x+5)=(7x4)
+x=y(x+5)=(7x4)
x=y(x+5)=(7x4)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+5|=|7x4|
x=+y , +x=y(x+5)=(7x4)
x=y , x=y(x+5)=(7x4)

2. Solve the two equations for x

13 additional steps

(x+5)=(7x-4)

Subtract from both sides:

(x+5)-7x=(7x-4)-7x

Group like terms:

(x-7x)+5=(7x-4)-7x

Simplify the arithmetic:

-6x+5=(7x-4)-7x

Group like terms:

-6x+5=(7x-7x)-4

Simplify the arithmetic:

6x+5=4

Subtract from both sides:

(-6x+5)-5=-4-5

Simplify the arithmetic:

6x=45

Simplify the arithmetic:

6x=9

Divide both sides by :

(-6x)-6=-9-6

Cancel out the negatives:

6x6=-9-6

Simplify the fraction:

x=-9-6

Cancel out the negatives:

x=96

Find the greatest common factor of the numerator and denominator:

x=(3·3)(2·3)

Factor out and cancel the greatest common factor:

x=32

10 additional steps

(x+5)=-(7x-4)

Expand the parentheses:

(x+5)=-7x+4

Add to both sides:

(x+5)+7x=(-7x+4)+7x

Group like terms:

(x+7x)+5=(-7x+4)+7x

Simplify the arithmetic:

8x+5=(-7x+4)+7x

Group like terms:

8x+5=(-7x+7x)+4

Simplify the arithmetic:

8x+5=4

Subtract from both sides:

(8x+5)-5=4-5

Simplify the arithmetic:

8x=45

Simplify the arithmetic:

8x=1

Divide both sides by :

(8x)8=-18

Simplify the fraction:

x=-18

3. List the solutions

x=32,-18
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+5|
y=|7x4|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.