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Solution - Absolute value equations

Exact form: x=3,13
x=3 , \frac{1}{3}
Decimal form: x=3,0.333
x=3 , 0.333

Other Ways to Solve

Absolute value equations

Step-by-step explanation

1. Rewrite the equation without absolute value bars

Use the rules:
|x|=|y|x=±y and |x|=|y|±x=y
to write all four options of the equation
|x+5|=|5x7|
without the absolute value bars:

|x|=|y||x+5|=|5x7|
x=+y(x+5)=(5x7)
x=y(x+5)=(5x7)
+x=y(x+5)=(5x7)
x=y(x+5)=(5x7)

When simplified, equations x=+y and +x=y are the same and equations x=y and x=y are the same, so we end up with only 2 equations:

|x|=|y||x+5|=|5x7|
x=+y , +x=y(x+5)=(5x7)
x=y , x=y(x+5)=(5x7)

2. Solve the two equations for x

13 additional steps

(x+5)=(5x-7)

Subtract from both sides:

(x+5)-5x=(5x-7)-5x

Group like terms:

(x-5x)+5=(5x-7)-5x

Simplify the arithmetic:

-4x+5=(5x-7)-5x

Group like terms:

-4x+5=(5x-5x)-7

Simplify the arithmetic:

4x+5=7

Subtract from both sides:

(-4x+5)-5=-7-5

Simplify the arithmetic:

4x=75

Simplify the arithmetic:

4x=12

Divide both sides by :

(-4x)-4=-12-4

Cancel out the negatives:

4x4=-12-4

Simplify the fraction:

x=-12-4

Cancel out the negatives:

x=124

Find the greatest common factor of the numerator and denominator:

x=(3·4)(1·4)

Factor out and cancel the greatest common factor:

x=3

12 additional steps

(x+5)=-(5x-7)

Expand the parentheses:

(x+5)=-5x+7

Add to both sides:

(x+5)+5x=(-5x+7)+5x

Group like terms:

(x+5x)+5=(-5x+7)+5x

Simplify the arithmetic:

6x+5=(-5x+7)+5x

Group like terms:

6x+5=(-5x+5x)+7

Simplify the arithmetic:

6x+5=7

Subtract from both sides:

(6x+5)-5=7-5

Simplify the arithmetic:

6x=75

Simplify the arithmetic:

6x=2

Divide both sides by :

(6x)6=26

Simplify the fraction:

x=26

Find the greatest common factor of the numerator and denominator:

x=(1·2)(3·2)

Factor out and cancel the greatest common factor:

x=13

3. List the solutions

x=3,13
(2 solution(s))

4. Graph

Each line represents the function of one side of the equation:
y=|x+5|
y=|5x7|
The equation is true where the two lines cross.

Why learn this

We encounter absolute values almost daily. For example: If you walk 3 miles to school, do you also walk minus 3 miles when you go back home? The answer is no because distances use absolute value. The absolute value of the distance between home and school is 3 miles, there or back.
In short, absolute values help us deal with concepts like distance, ranges of possible values, and deviation from a set value.